How to Maximize Element Frequency in Array with Operations

LeetCode POTD 🫠: Description: You are given an integer array target. You have an integer array initial of the same size as target with all elements initially zeros. In one operation you can choose any subarray from initial and increment each value by one. Return the minimum number of operations to form a target array from initial. The test cases are generated so that the answer fits in a 32-bit integer. Here's my solution: https://lnkd.in/gUKAaRQG #Python #DSA #Leetcode #DailyChallenge

🚀 Daily LeetCode Challenge: Check If All 1’s Are at Least K Places Apart Today’s problem tested the importance of clean logic and careful return placement. The challenge: Given a binary array nums and an integer k, determine if all 1s are at least k indices apart. 🔎 Approach Track the index of the last seen 1. For each new 1, check the gap with the previous one. If the gap is smaller than k, return False. Otherwise, update the last index and continue. If no violations are found, return True. 🔗 https://lnkd.in/grFSDb3w #LeetCode #DailyCodingChallenge #Python #Algorithms #ProblemSolving #CodingJourney #100DaysOfCode #SoftwareEngineering

LeetCode POTD 😁: Description: You are given an array nums of n integers and two integers k and x. The x-sum of an array is calculated by the following procedure: -> Count the occurrences of all elements in the array. -> Keep only the occurrences of the top x most frequent elements. If two elements have the same number of occurrences, the element with the bigger value is considered more frequent. -> Calculate the sum of the resulting array. Note that if an array has less than x distinct elements, its x-sum is the sum of the array. Return an integer array answer of length n - k + 1 where answer[i] is the x-sum of the subarray nums[i..i + k - 1]. Here's my solution: https://lnkd.in/g6gjzEq7 #Python #DSA #Leetcode #DailyChallenge

Day 62 Of #100DaysOfCode Problem #3354: Make Array Elements Equal to Zero Successfully solved today’s problem with an optimized solution achieving 93.09% runtime efficiency and 95.74% memory optimization! 🚀 🧩 Problem Insight: Given an integer array, the task is to determine the number of valid selections of a starting index and direction that reduce all array elements to zero by following specific movement and decrement rules. ⚙️ Approach: Used prefix/suffix summation logic to track balance between left and right movements. Calculated total sum and suffix sums efficiently to identify valid starting points. Achieved O(n) time complexity using cumulative tracking. 🧠 Language: Python ✅ Result: Accepted | Beats 93.09% in Runtime, 95.74% in Memory #LeetCode #Python #ProblemSolving #CodingChallenge #Mythyly #DailyPractice #DSA #ProgrammingJourney #WomenInTech

LeetCode POTD 💫: Description : You are given a string s consisting of digits. Perform the following operation repeatedly until the string has exactly two digits: -> For each pair of consecutive digits in s, starting from the first digit, calculate a new digit as the sum of the two digits modulo 10. -> Replace s with the sequence of newly calculated digits, maintaining the order in which they are computed. Return true if the final two digits in s are the same; otherwise, return false. Here's my solution: https://lnkd.in/gQGnGakf #Python #DSA #Leetcode #DailyChallenge #Easy

Python Day 5 Tip: Difference Between append() and extend() Both are used to add elements to a list , but they work differently! # Example list1 = [1, 2, 3] list1.append([4, 5]) print(list1) #output is [1, 2, 3, [4, 5]] list1 = [1, 2, 3] list1.extend([4, 5]) print(list1) #output is [1, 2, 3, 4, 5] 1) append() adds the entire object as a single element. 2) extend() adds each element from the iterable individually. Tip: Use append() for single items and extend() for adding multiple items at once. #Python #30DaysOfpythonCode #PythonTips #Coding #FullStackDeveloper #LearnPython #PythonLearning

💡 LeetCode #21 — Merge Two Sorted Lists 📘 Problem: You are given the heads of two sorted linked lists list1 and list2. Merge them into one sorted linked list and return the head of the new list. 🧠 Approach: Use a dummy node to simplify the process. Compare nodes from both lists one by one. Attach the smaller node to the merged list. Once one list is empty, connect the remaining nodes from the other list. ⚙️ Complexity: ⏱ Time: O(m + n) — traverse both lists once 💾 Space: O(1) — uses constant extra space 💬 Takeaway: This is a great example of the two-pointer technique and dummy node pattern, useful in many linked list problems. #LeetCode #Python #DataStructures #LinkedLists #CodingInterview #DSA

Test Python code not "by feel," but through three levels. First, unit tests for basic logic, then fixtures for the real environment (files, databases, HTTP mocks), and on top hypothesis for the automatic search for hidden bugs. This way, the tests will be short, and the coverage and reliability will be maximal. That is the goal of hypothesis. To learn more about hypothesis check the documentation here https://hypothesis.works/ Did you know it before for testing ? To discover more tips like this let connected :) #python #test #pytest #hypothesis #fastapi #django

🚀 The finally Clause in try...except Blocks (Python) The `finally` clause in a `try...except` block is always executed, regardless of whether an exception was raised or not. This makes it ideal for cleanup tasks, such as closing files, releasing resources, or resetting state. The `finally` clause ensures that these critical operations are performed even if an exception occurs, preventing resource leaks and ensuring the program's integrity. It's an essential part of robust exception handling. Learn more on our website: https://techielearns.com #Python #PythonDev #DataScience #WebDev #professional #career #development

LeetCode POTD 💫: Description: An integer x is numerically balanced if for every digit d in the number x, there are exactly d occurrences of that digit in x. Given an integer n, return the smallest numerically balanced number strictly greater than n. Here's my solution: https://lnkd.in/g5U3MZ8i #Python #DSA #Leetcode #DailyChallenge #Medium #HashMap