LeetCode POTD 🫠: Description: You are given an integer array target. You have an integer array initial of the same size as target with all elements initially zeros. In one operation you can choose any subarray from initial and increment each value by one. Return the minimum number of operations to form a target array from initial. The test cases are generated so that the answer fits in a 32-bit integer. Here's my solution: https://lnkd.in/gUKAaRQG #Python #DSA #Leetcode #DailyChallenge
How to solve LeetCode POTD with Python
More Relevant Posts
-
LeetCode POTD 💫: Description: An integer x is numerically balanced if for every digit d in the number x, there are exactly d occurrences of that digit in x. Given an integer n, return the smallest numerically balanced number strictly greater than n. Here's my solution: https://lnkd.in/g5U3MZ8i #Python #DSA #Leetcode #DailyChallenge #Medium #HashMap
To view or add a comment, sign in
-
-
Python Day 5 Tip: Difference Between append() and extend() Both are used to add elements to a list , but they work differently! # Example list1 = [1, 2, 3] list1.append([4, 5]) print(list1) #output is [1, 2, 3, [4, 5]] list1 = [1, 2, 3] list1.extend([4, 5]) print(list1) #output is [1, 2, 3, 4, 5] 1) append() adds the entire object as a single element. 2) extend() adds each element from the iterable individually. Tip: Use append() for single items and extend() for adding multiple items at once. #Python #30DaysOfpythonCode #PythonTips #Coding #FullStackDeveloper #LearnPython #PythonLearning
To view or add a comment, sign in
-
Does your boss want to see progress made towards expunging #CVEs from network devices? Would he appreciate seeing this information in a graph? Check out Andrew Mulheirn's #ForwardCommunity tutorial on how to graph CVE numbers over time using the #ForwardAPI, a python script, and #Grafana. https://hubs.li/Q03P2F090
To view or add a comment, sign in
-
-
Test Python code not "by feel," but through three levels. First, unit tests for basic logic, then fixtures for the real environment (files, databases, HTTP mocks), and on top hypothesis for the automatic search for hidden bugs. This way, the tests will be short, and the coverage and reliability will be maximal. That is the goal of hypothesis. To learn more about hypothesis check the documentation here https://hypothesis.works/ Did you know it before for testing ? To discover more tips like this let connected :) #python #test #pytest #hypothesis #fastapi #django
To view or add a comment, sign in
-
-
🐍 For Loop vs Lambda - The Python Showdown! Two ways to get things done, two very different 𝗽𝗲𝗿𝘀𝗼𝗻𝗮𝗹𝗶𝘁𝗶𝗲𝘀 👇 🔁 For Loop: The “hardworking” one goes 𝘀𝘁𝗲𝗽 𝗯𝘆 𝘀𝘁𝗲𝗽, makes sure everyone gets processed. Readable, reliable, and maybe a bit old-school. ⚡ Lambda Function: The “minimalist” gets the job done in 𝗼𝗻𝗲 𝗹𝗶𝗻𝗲. No drama, no names, just results. When to use what? 𝙐𝙨𝙚 𝙖 𝙛𝙤𝙧 𝙡𝙤𝙤𝙥 𝙬𝙝𝙚𝙣 𝙘𝙡𝙖𝙧𝙞𝙩𝙮 𝙢𝙖𝙩𝙩𝙚𝙧𝙨. 𝙐𝙨𝙚 𝙖 𝙡𝙖𝙢𝙗𝙙𝙖 𝙬𝙝𝙚𝙣 𝙨𝙥𝙚𝙚𝙙 𝙖𝙣𝙙 𝙗𝙧𝙚𝙫𝙞𝙩𝙮 𝙢𝙖𝙩𝙩𝙚𝙧. Both are powerful one’s like writing a story, the other’s like crafting a tweet. #Python #DataScience #CodingLife #Lambda #ForLoop #ProgrammingHumor #Developers #DataMantra
To view or add a comment, sign in
-
-
LeetCode POTD 🫠: Description: You are given an integer array nums and two integers k and numOperations. You must perform an operation numOperations times on nums, where in each operation you: -> Select an index i that was not selected in any previous operations. -> Add an integer in the range [-k, k] to nums[i]. Return the maximum possible frequency of any element in nums after performing the operations. Here's my solution: https://lnkd.in/gmVVWR38 #Python #DSA #Leetcode #DailyChallenge #Medium
To view or add a comment, sign in
-
-
How to remove duplicates from an array?* *Explanation:* Use a set to filter out duplicates. To preserve order, track seen elements. *Python:* ```python def remove_duplicates(arr): seen = set() result = [] for num in arr: if num not in seen: seen.add(num) result.append(num) return result sharafadin mahmodi
To view or add a comment, sign in
-
🚀 Daily LeetCode Challenge: Check If All 1’s Are at Least K Places Apart Today’s problem tested the importance of clean logic and careful return placement. The challenge: Given a binary array nums and an integer k, determine if all 1s are at least k indices apart. 🔎 Approach Track the index of the last seen 1. For each new 1, check the gap with the previous one. If the gap is smaller than k, return False. Otherwise, update the last index and continue. If no violations are found, return True. 🔗 https://lnkd.in/grFSDb3w #LeetCode #DailyCodingChallenge #Python #Algorithms #ProblemSolving #CodingJourney #100DaysOfCode #SoftwareEngineering
To view or add a comment, sign in
-
-
🚀 Calculating Time Differences with Timedelta (Python) You can calculate the difference between two `datetime` objects by subtracting one from the other. The result is a `timedelta` object representing the duration between the two points in time. This is useful for measuring elapsed time, calculating deadlines, or determining the length of events. Ensure both `datetime` objects are timezone-aware or naive to avoid incorrect results. #Python #PythonDev #DataScience #WebDev #professional #career #development
To view or add a comment, sign in
-
Explore content categories
- Career
- Productivity
- Finance
- Soft Skills & Emotional Intelligence
- Project Management
- Education
- Technology
- Leadership
- Ecommerce
- User Experience
- Recruitment & HR
- Customer Experience
- Real Estate
- Marketing
- Sales
- Retail & Merchandising
- Science
- Supply Chain Management
- Future Of Work
- Consulting
- Writing
- Economics
- Artificial Intelligence
- Employee Experience
- Workplace Trends
- Fundraising
- Networking
- Corporate Social Responsibility
- Negotiation
- Communication
- Engineering
- Hospitality & Tourism
- Business Strategy
- Change Management
- Organizational Culture
- Design
- Innovation
- Event Planning
- Training & Development