LeetCode POTD 😁: Description: You are given an array nums of n integers and two integers k and x. The x-sum of an array is calculated by the following procedure: -> Count the occurrences of all elements in the array. -> Keep only the occurrences of the top x most frequent elements. If two elements have the same number of occurrences, the element with the bigger value is considered more frequent. -> Calculate the sum of the resulting array. Note that if an array has less than x distinct elements, its x-sum is the sum of the array. Return an integer array answer of length n - k + 1 where answer[i] is the x-sum of the subarray nums[i..i + k - 1]. Here's my solution: https://lnkd.in/g6gjzEq7 #Python #DSA #Leetcode #DailyChallenge
How to calculate x-sum of subarrays in Python
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LeetCode POTD 💫: Description: You are given an array nums of n integers and two integers k and x. The x-sum of an array is calculated by the following procedure: -> Count the occurrences of all elements in the array. -> Keep only the occurrences of the top x most frequent elements. If two elements have the same number of occurrences, the element with the bigger value is considered more frequent. -> Calculate the sum of the resulting array. Note that if an array has less than x distinct elements, its x-sum is the sum of the array. Return an integer array answer of length n - k + 1 where answer[i] is the x-sum of the subarray nums[i..i + k - 1]. Here's my solution: https://lnkd.in/gmUKJuq2 #Python #DSA #Leetcode #DailyChallenge #Hard
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LeetCode POTD 💫: Description: Given an integer n, you must transform it into 0 using the following operations any number of times: -> Change the rightmost (0th) bit in the binary representation of n. -> Change the ith bit in the binary representation of n if the (i-1)th bit is set to 1 and the (i-2)th through 0th bits are set to 0. Return the minimum number of operations to transform n into 0. (Big thanks to Mazhar Imam Khan for his clear and insightful video explanation — saw it just in time and it made all the difference 🙌) Here's my solution: https://lnkd.in/gTU_uPUd #Python #DSA #Leetcode #DailyChallenge #Hard #BitManipulation
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69. Sqrt(x) Solved Easy Topics Companies Hint Given a non-negative integer x, return the square root of x rounded down to the nearest integer. The returned integer should be non-negative as well. You must not use any built-in exponent function or operator. For example, do not use pow(x, 0.5) in c++ or x ** 0.5 in python. Example 1: Input: x = 4 Output: 2 Explanation: The square root of 4 is 2, so we return 2. Example 2: Input: x = 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
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🔷 Day 19- 30DaysChallenge(Leetcode Problem): Pascal's Triangle 🌟 Problem: Given an integer numRows, return the first numRows of Pascal's triangle. In Pascal's triangle, each number is the sum of the two numbers directly. 🧠Solution: class Solution: def generate(self, numRows: int) -> List[List[int]]: res=[[1]] for i in range(numRows-1): temp=[0]+res[-1]+[0] row=[] for j in range(len(res[-1])+1): row.append(temp[j]+temp[j+1]) res.append(row) return res #DSA #Python #CodingChallenge #30dayschallenge #Leetcode
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🧩 Day 39 — Find First and Last Position of Element in Sorted Array (LeetCode 34) 📝 Problem -Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value. -If target is not found in the array, return [-1, -1]. You must write an algorithm with O(log n) runtime complexity 🔁 Approach -Use binary search twice — once to find the first occurrence and once to find the last occurrence. -For the first position: -When nums[mid] == target, move left (right = mid - 1) to continue searching earlier indices. -For the last position: -When nums[mid] == target, move right (left = mid + 1) to continue searching later indices. -If the target does not exist in the array, return [-1, -1] 📊 Complexity -Time Complexity: O(log n) -Space Complexity: O(1) 🔑 Concepts Practiced -Binary Search -Divide and Conquer -Edge Case Handling #Leetcode #Python #DSA #BinarySearch #Divide
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Built a quick reference guide for RAG patterns. Spent some time documenting 5 common patterns I kept seeing in production systems: • Semantic chunking • HyDE (query expansion) • Re-ranking • Metadata filtering • Query decomposition Each one has working Python code and notes on when it's worth using vs. when it's overkill. Also threw in some case studies with actual numbers ($900K-$2.3M impact range) from real implementations I researched. Nothing groundbreaking - just a clean reference for the trade-offs (latency, cost, quality) since I couldn't find one that laid it out clearly. Live docs: https://lnkd.in/edsUB5mA Code: https://lnkd.in/e9Xqrme6 #MachineLearning #RAG #Python
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🚀 Day 43 of #100DaysOfDSA 💡 Problem: 993. Cousins in Binary Tree 🔗 LeetCode: https://lnkd.in/djrWKuC4 🧠 Approach: - Used DFS to record the depth and parent of both target nodes (x and y). - Compared their depths and parents to check if they are cousins (same level, different parents). - Used recursion for clean and efficient traversal. 📚 Learnings: - Strengthened understanding of tree traversal using recursion. - Learned to track multiple attributes (depth, parent) simultaneously. - Improved logical reasoning for binary tree relationship problems. 👨💻 LeetCode Profile: https://lnkd.in/dGQwSXjb #100DaysOfDSA #Day43 #LeetCode #Python #BinaryTree #DFS #Recursion #ProblemSolving #CodingChallenge
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💡 LeetCode #21 — Merge Two Sorted Lists 📘 Problem: You are given the heads of two sorted linked lists list1 and list2. Merge them into one sorted linked list and return the head of the new list. 🧠 Approach: Use a dummy node to simplify the process. Compare nodes from both lists one by one. Attach the smaller node to the merged list. Once one list is empty, connect the remaining nodes from the other list. ⚙️ Complexity: ⏱ Time: O(m + n) — traverse both lists once 💾 Space: O(1) — uses constant extra space 💬 Takeaway: This is a great example of the two-pointer technique and dummy node pattern, useful in many linked list problems. #LeetCode #Python #DataStructures #LinkedLists #CodingInterview #DSA
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Happy to share my latest project... A Python package and interactive CLI for filtering, analyzing, and exporting multi-format log files. It supports custom regex parsing, smart filtering by level/keyword/date, clean exports (CSV/JSON), and colourful summaries. All from your terminal. Built with Typer 🌬 Check it out on PyPi: https://lnkd.in/d6VJCn7U Repository at: https://lnkd.in/dnHzsG_x Video demo below! 🎥 #Python #CLI #LogAnalysis
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