Not every arithmetic operator works with every type in Python. 🧮 "hi" + 5 is a TypeError. 3 * "ab" is "ababab". And // and % don't work with complex numbers. I wrote a short guide that clears it up: ✅ Which operators work with int, float, bool, complex, and string ✅ Result type: when you get int vs float vs complex vs string ✅ String: only + (concatenation) and * (repeat with int) ✅ Complex: no // or % — and why ✅ Division by zero, int+string, float*string — what to avoid ✅ Result-type summary + practice problems with answers ~7 min read. Straight to the point. https://lnkd.in/gwg3vgZf #Python #Programming #Coding #Beginners #LearnToCode #DataTypes #ArithmeticOperators #Tech #SoftwareDevelopment #CodingTips
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💫A simple but powerful Python logic: Palindrome Check🌟 💥A string is a palindrome if it reads the same forward and backward. Examples: radar level madam Python makes this extremely simple: word = "radar" if word == word[::-1]: print("Palindrome") else: print("Not a Palindrome") The trick here is: [::-1] reverses the string. So we simply compare: original string == reversed string This concept is commonly used in: Coding interviews String manipulation problems Algorithm practice Sometimes the smartest solution is also the simplest. What was the first string problem you solved in Python? #Python #Programming #Coding #Learn ToCode #PythonLearning #Developer #Software Engineering
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A simple but powerful Python logic: Palindrome Check A string is a palindrome if it reads the same forward and backward. Examples: radar level madam Python makes this extremely simple: word = "radar" if word == word[::-1]: print("Palindrome") else: print("Not a Palindrome") The trick here is: [::-1] → reverses the string. So we simply compare: original string == reversed string This concept is commonly used in: • Coding interviews • String manipulation problems • Algorithm practice Sometimes the smartest solution is also the simplest. What was the first string problem you solved in Python? #Python #Programming #Coding #LearnToCode #PythonLearning #Developer #SoftwareEngineering #CodingInterview #100DaysOfCode #Tech
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Day 7/100 – #100DaysOfCode 🚀 Solved LeetCode #27 – Remove Element (Python). Today I practiced the Two Pointer technique to remove all occurrences of a given value in-place and return the new length of the array. Approach: 1) Initialize a pointer k to track the position of valid elements. 2) Traverse the array using index i. 3) If nums[i] is not equal to the given value, assign it to nums[k]. 4) Increment k to expand the valid portion of the array. 5) Return k as the new length. Time Complexity: O(n) Space Complexity: O(1) – In-place solution Learning how in-place array manipulation works step by step 💪 #LeetCode #Python #DSA #Arrays #TwoPointers #ProblemSolving #100DaysOfCode
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A tiny Python trick I learned while using Claude Code While building an app with Claude Code, I noticed it repeatedly using a neat Python pattern I had somehow missed for years. d = {'A': 1, 'B': 2} e = {**d, 'A': 2} print(e) # {'A': 2, 'B': 2} This looks trivial. But the idea behind it is powerful: start from a default dictionary and selectively override fields. It’s a small trick, but it creates a very clean pattern for: ✅ Generating test cases ✅ Configuration overrides ✅ Scenario simulation Sometimes the most useful ideas are not big algorithms. They are small patterns that quietly make code cleaner. #pythonic #claudecode #claude #software #pythontricks #python
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🔢 Day 23 – Matrix Problems in Python 🚀 Today, I continued my Python problem-solving journey by practicing Matrix problems. Matrices help strengthen nested loops, indexing, and logical thinking, which are essential for coding interviews and real-world problem solving. 📌 Topics Covered: ✔️ Accessing rows and columns ✔️ Printing specific rows or columns ✔️ Diagonal elements (Primary & Secondary) ✔️ Row-wise and column-wise operations ✔️ Matrix traversal using loops #Day23 #Python #Matrix #ProblemSolving #LearningInPublic #CodingJourney
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Find the Bug! 🐛🔍 def add(a, b=[]): b.append(a) return b print(add(1)) print(add(2)) What is the second output? 🖨️ A) [2] B) [1, 2] C) [2, 1] This is the most dangerous default argument in Python. ⚠️ 👇 **Comment A, B, or C!** Did you spot the mutable default trap? 🪤 #Debugging #Python #CodingChallenge #BugBounty #Tech
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🚀 Day 24 – pow() in Python Today I explored the pow() function in Python! print(pow(2, 3)) 🔹 Use: Power calculation 🔹 pow(2, 3) means 2 raised to the power of 3 🔹 Output: 8 The pow() function is an alternative to the exponent operator (**). So, pow(2, 3) is the same as 2 ** 3. It’s a simple yet powerful function that makes mathematical operations clean and readable in Python. 🧮 Excited to keep building strong fundamentals one function at a time! #Python #30DaysOfCode #CodingJourney #LearnPython #Programming
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Day 24/100 – #100DaysOfCode 🚀 Solved LeetCode #747 – Largest Number At Least Twice of Others (Dominant Index) (Python). Today I practiced array traversal and comparison logic to find the dominant index in the array. Approach: 1) Find the largest element in the array and its index. 2) Traverse through the array. 3) For every other element, check if the largest is at least twice of it. 4) If any element violates this condition, return -1. 5) If all conditions are satisfied, return the index of the largest element. Time Complexity: O(n) Space Complexity: O(1) Learning how simple comparisons can solve array problems efficiently 💪 #LeetCode #Python #DSA #Arrays #ProblemSolving #100DaysOfCode
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Finding Maximum Sum of k Consecutive Elements in Python Check out this simple sliding window trick to get the maximum sum of k consecutive numbers in an array. I used my own code to solve it: Python Copy code nums = [7,1,5,1,3,2] k = 3 n = len(nums) window = sum(nums[:k]) sums = window for i in range(k,n): window = window - nums[i-k] + nums[i] if sums < window: sums = window print(sums) How it works: Start with the sum of the first k numbers Slide the window by removing the first number and adding the next Keep track of the maximum sum Fast, simple, and efficient! #Python #DSA #Coding #Algorithms #LearnByDoing #DeveloperLife
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Day 30/100 – #100DaysOfCode 🚀 Solved LeetCode #1299 – Replace Elements with Greatest Element on Right Side (Python). Today I practiced reverse traversal to efficiently replace each element with the greatest element on its right. Approach: 1) Initialize max_right = -1. 2) Traverse the array from right to left. 3) Store the current element in a temporary variable. 4) Replace the current element with max_right. 5) Update max_right as the maximum of max_right and the stored value. 6) Continue until the entire array is processed. Time Complexity: O(n) Space Complexity: O(1) Learning how reverse traversal can simplify problems efficiently 💪 #LeetCode #Python #DSA #Arrays #ProblemSolving #100DaysOfCode
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