Python Mutable Default Argument Bug

How to annotate *args in #Python? Just set the elements' type; we know it's a tuple: def mysum(*args:int) -> int: total = 0 for n in args: total += n return total Normally, tuples contain different types. In args, we assume all values have the same type.

⚡ Python Tip: list.append(x) vs list.extend(x) 👉 append(): Adds one element [1,2].append([3,4]) → [1,2,[3,4]] 👉 extend(): Adds elements individually [1,2].extend([3,4]) → [1,2,3,4] 📌 Small difference. Big impact. #Python #CodingTips #LearnPython

LeetCode POTD 💫: Description: Given two n x n binary matrices mat and target, return true if it is possible to make mat equal to target by rotating mat in 90-degree increments, or false otherwise. Here's my solution: https://lnkd.in/gx6Y6bUH #Python #DSA #Leetcode #DailyChallenge #Matrix

🧠 Python Logic Check — Quick Challenge Consider the following snippet: x = 10 x += x == 10 print(x) At first glance, it looks straightforward — but it tests your understanding of how Python handles boolean expressions. 💡 Question: What will be the output? A) 10 B) 11 C) True D) Error 📌 Small details like this often separate beginners from experienced developers. 💬 Drop your answer in the comments — and explain your reasoning if you can. #Python #SoftwareEngineering #CodingChallenge #DeveloperMindset #Learning

Day 31/100 – #100DaysOfCode 🚀 Solved LeetCode #1346 – Check If N and Its Double Exist (Python). Today I practiced brute-force comparison to check whether there exist two indices i and j such that arr[i] = 2 * arr[j]. Approach: 1) Use two nested loops to check all possible pairs. 2) Ensure that i ≠ j. 3) For each pair, check if arr[i] == 2 * arr[j]. 4) If condition is satisfied, return True. 5) If no such pair is found, return False. Time Complexity: O(n²) Space Complexity: O(1) Starting with brute force helps build understanding before optimization 💪 #LeetCode #Python #DSA #Arrays #BruteForce #ProblemSolving #100DaysOfCode

#4 — Formatted Output / Still No Function f-strings make the output human-readable. But the logic is still loose in the script. Part of the series: One Problem – Different Approaches Start here: https://lnkd.in/dxPDnRXZ #OneProblemDifferentApproaches #CelsiusToFahrenheit #Python #sedatçapar

Python Challenge – Can you solve this? Today was all about deep-diving into Lists vs. Sets and I came across a common mistake that we can sometimes overlook. Let’s test your Python understanding👇 numbers = [1, 2, 3] numbers.append([4, 5]) print(len(numbers)) A) 3 B) 4 C) 5 D) Error It’s a classic interview question that tests if you truly understand how Python handles memory and lists. Day 15/30 #30DaysOfCode #DataStructures #Day15 #PythonQuiz

#7 — Docstring Added / Now It Documents Itself A good function tells you what it does. No need to read the code. Part of the series: One Problem – Different Approaches Start here: https://lnkd.in/dxPDnRXZ #OneProblemDifferentApproaches #CelsiusToFahrenheit #Python #sedatçapar

Tiny Python upgrade for cleaner analytics code: Use Counter instead of manual dict increments. You get frequency maps in one pass and top-N insights with most_common(). Less boilerplate, fewer mistakes, faster review. Mini pattern: - counts = Counter(values) - top = counts.most_common(3) - act on thresholds #Python #CodingTips #Backend #DevTips #SoftwareEngineering

When working with different data types, Python requires explicit conversion. Here, numbers and boolean values are converted into strings before combining them. This ensures that all parts are of the same type during concatenation. Answer: A) 52False #Python #TypeCasting #MathModule #PythonBasics #LearningInPublic #ProblemSolving #CodingPractice