Annotate args in Python with Type Hints

#7 — Docstring Added / Now It Documents Itself A good function tells you what it does. No need to read the code. Part of the series: One Problem – Different Approaches Start here: https://lnkd.in/dxPDnRXZ #OneProblemDifferentApproaches #CelsiusToFahrenheit #Python #sedatçapar

Day 31/100 – #100DaysOfCode 🚀 Solved LeetCode #1346 – Check If N and Its Double Exist (Python). Today I practiced brute-force comparison to check whether there exist two indices i and j such that arr[i] = 2 * arr[j]. Approach: 1) Use two nested loops to check all possible pairs. 2) Ensure that i ≠ j. 3) For each pair, check if arr[i] == 2 * arr[j]. 4) If condition is satisfied, return True. 5) If no such pair is found, return False. Time Complexity: O(n²) Space Complexity: O(1) Starting with brute force helps build understanding before optimization 💪 #LeetCode #Python #DSA #Arrays #BruteForce #ProblemSolving #100DaysOfCode

Day 53/100 – #100DaysOfCode 🚀 Solved LeetCode #125 – Valid Palindrome (Python). Today I practiced string cleaning and validation to check whether a given string is a palindrome. Approach: 1) Traverse the string and keep only alphanumeric characters. 2) Convert all characters to lowercase. 3) Build a cleaned string. 4) Compare the string with its reverse. 5) If both are equal, return True; otherwise, return False. Time Complexity: O(n) Space Complexity: O(n) Learning how preprocessing simplifies string problems 💪 #LeetCode #Python #DSA #Strings #ProblemSolving #100DaysOfCode

Day 4 – Python Deep Dive 🚀 Topic: Mutable vs Immutable Immutable: int, string, tuple Mutable: list, dictionary Example: x = "hello" x[0] = "H" ❌ (error) 👉 Key takeaway: Immutable objects cannot be changed after creation. This impacts memory and performance. #Python #DeveloperThinking

#6 — Constants Inside / Formula Speaks Same function. Cleaner design. Part of the series: One Problem – Different Approaches Start here: https://lnkd.in/dxPDnRXZ #OneProblemDifferentApproaches #CelsiusToFahrenheit #Python #sedatçapar

Here's a Python dictionary merge challenge from @dontmisstmr — can you get it right without running the code? dict1 = {"name": "Alice", "age": 25} dict2 = {"city": "Noida", "age": 26} merged = dict1 | dict2 print(merged) The | operator was introduced in Python 3.9. When both dicts share a key, which value wins? Drop your answer in the comments! #Python #SoftwareDevelopment #CodingChallenge #ProgrammingTips #TechCommunity

DAY 28 OF PYTHON CHALLENGE #Wapp for append() function (dynamically) l=[ ] n=int(input("enter how many entries u want?")) for i in range(n): a=input("enter the elements") l.append(a) print(l) output: enter how many entries u want 3 enter the element 100 enter the element abc enter the element 9.9 ['100','abc','9.9'] #coding #python #challenge #mca #30days

Day 42/100 – #100DaysOfCode 🚀 Solved LeetCode #2574 – Left and Right Sum Differences (Python). Today I practiced prefix sum logic to calculate the absolute difference between left and right sums for each index. Approach: 1) Calculate the total sum of the array. 2) Initialize leftSum = 0. 3) Traverse the array. 4) For each index, compute rightSum = total - leftSum - nums[i]. 5) Calculate the absolute difference and append it to the result. 6) Update leftSum by adding nums[i]. Time Complexity: O(n) Space Complexity: O(n) Understanding prefix sum helps solve problems efficiently 💪 #LeetCode #Python #DSA #Arrays #PrefixSum #ProblemSolving #100DaysOfCode

Two sum: Using dictionary (Optimized Solution) Instead of checking every pair: For each number, calculate what number is required. Formula to calculate required : required = target - current_number  Time complexity → O(n) #Python #LogicBuilding #ProblemSolvingSkills #Beginners

🚀 Stop doing this in Python: it turns O(n) into O(n²) without you noticing In Python (and many other languages), strings are immutable. That means every time you concatenate a string, a new object is created instead of modifying the existing one. So if you do this repeatedly inside a loop, you’re not really “adding” to the string, you’re rebuilding it from scratch again and again, which becomes increasingly expensive. Reference: https://lnkd.in/gt_gw3bZ #python #coding #pythontips #pythonprogramming