Day 5 | Problem 1 – Score of a String Today I practised calculating the score of a string by finding the absolute difference between adjacent characters. Approach used: • Traverse the string from left to right • Calculate the absolute ASCII difference between consecutive characters • Add each difference to a running sum • Return the final score This problem helped me better understand character handling in strings, ASCII values, and loop-based traversal. #Java #DSA #StringProblems #LearningInPublic #Consistency
Calculating String Score with ASCII Difference
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Day: 43/365 📌 LeetCode POTD: Binary Number with Alternating Bits Easy Key takeaways/Learnings from this problem: 1. This one shows how clean bit tricks can replace messy string checks when working with binary patterns. 2. Big takeaway: sometimes a small observation (like using XOR or shifting) turns a pattern problem into a super neat one-liner. #POTD #365DaysOfCode #DSA #Java #ProblemSolving #LearningInPublic #Consistency 🥷
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Day 11/30 – 3Sum Closest 🚀 Problem: Find three numbers whose sum is closest to a given target. Approach: • Sort the array • Fix one element • Use Two Pointers • Track minimum difference using Math.abs() Key Idea: Instead of finding exact zero (like 3Sum), minimize the distance from target. Time Complexity: O(n²) Space Complexity: O(1) #30DaysOfCode #Java #DSA #TwoPointers #InterviewPrep
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𝗬𝗼𝘂 𝗵𝗮𝘃𝗲 𝗯𝗲𝗲𝗻 𝘂𝘀𝗶𝗻𝗴 𝗕𝗶𝗻𝗮𝗿𝘆 𝗦𝗲𝗮𝗿𝗰𝗵 𝘄𝗿𝗼𝗻𝗴. It is not just for sorted arrays. The real definition — "Eliminate HALF the search space with each decision." That one shift in thinking unlocks 20+ LeetCode problems. Swipe to see the template, live code, and 7 problems you can now solve with one pattern. 👇 Save this. 🔖 #DSA #BinarySearch #Java #LeetCode #CodingInterview #DebugWithPurpose
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Day 35 – Plus One Worked on a problem where a large integer is represented as an array of digits, and the task was to increment the number by one. Key Learnings: Traversing arrays from right to left to simulate digit addition Handling carry when a digit becomes 10 Managing edge cases where all digits are 9 by creating a new array #DSA #Java #Arrays #ProblemSolving #CodingPractice #LeetCode
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🚀 Day 76 of #100DaysOfCode Today I solved a string manipulation problem: Clear Digits 🧠 Problem: Given a string, whenever a digit appears, remove the previous character. Digits act like a backspace operation. 💡 Key Insight: Instead of modifying the string directly (since Strings are immutable in Java), I used a StringBuilder, which works like a stack: If character → append (push) If digit → delete last character (pop) 📌 What I Learned: StringBuilder is powerful for string modifications Always handle edge cases (like digit at the start) Many string problems are actually stack problems in disguise ⏱ Complexity: Time: O(n) Space: O(n) #Java #DSA #LeetCode #CodingJourney #100DaysOfCode #ProblemSolving
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LeetCode Problem || Check if Binary String Has at Most One Segment of Ones(1784)🚀 we need to check: The string should have only one continuous block of '1's. After a '0' appears, '1' should never appear again. ✨ Insight: Instead of manually counting segments using loops, we can simply check if "01" exists in the string. 📌 Time Complexity: O(n) Practicing problems like these helps improve pattern recognition and problem-solving efficiency. #LeetCode #DSA #Java #CodingPractice #ProblemSolving
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Day 7 | Problem 1 – Sentence Similarity III (LeetCode 1813) Solved Problem 1 by determining whether two sentences can become equal by inserting a group of words at exactly one position. Approach: • Split both sentences into word arrays using split(" ") • Ensured the smaller sentence is used as the base for comparison • Matched common words from the beginning (prefix match) • Matched common words from the end (suffix match) • Checked if prefix + suffix matches covered all words of the smaller sentence This problem strengthened my understanding of: • Two-pointer technique • String manipulation • Logical comparison of sequences Continuing my 15-Day 50+ String DSA Challenge 🚀 #DSA #Java #StringProblems #LeetCode #LearningInPublic #CodingJourney
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🚀 Day 18/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 1528. Shuffle String Used a direct indexing approach by placing each character at its correct position using the given indices array. ⏱️ Time Complexity: O(n) 📦 Space Complexity: O(n) A simple yet important problem to strengthen understanding of arrays and index mapping. 💪 Consistency continues 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency
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🚀 Day 96 of #100DaysOfCode Solved LeetCode #1461 – Check If a String Contains All Binary Codes of Size K ✅ A solid mix of sliding window + bit manipulation, where efficiency really matters. Key Takeaways: -> Using rolling hash / bitmask to track binary substrings -> Avoiding substring overhead for better performance -> Understanding the limit: total required codes = 2^k -> Early pruning with length checks for optimization Language: Java -> Runtime: 6 ms (Beats 100%) ⚡ -> Memory: 47.73 MB Almost at the finish line — one binary string at a time 💻🔥 #LeetCode #Java #BitManipulation #SlidingWindow #Strings #ProblemSolving #100DaysOfCode
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