LeetCode Binary Number with Alternating Bits Solution

Day: 44/365 📌 LeetCode POTD: Count Binary Substrings Easy Key takeaways/Learnings from this problem: 1. The real trick is noticing you don’t need to check every substring — just track lengths of consecutive 0s and 1s. 2. Big takeaway: many string problems become simple once you focus on grouping patterns instead of brute force counting. #POTD #365DaysOfCode #DSA #Java #ProblemSolving #LearningInPublic #Consistency 🥷

Day: 52/365 📌 LeetCode POTD: Minimum Operations to Equalize Binary String Level: Hard Key takeaways/Learnings from this problem: 1. This one really makes you think in terms of mismatched positions instead of raw characters. 2. Greedy feels tempting, but you need to carefully compare operation costs before deciding what to fix first. 3. It’s a good reminder that binary string problems often reduce to counting patterns smartly. 4. Biggest takeaway: always try to simplify the string into a difference representation — the solution usually becomes much clearer. #POTD #365DaysOfCode #DSA #Java #ProblemSolving #LearningInPublic #Consistency 🥷

LeetCode Problem || Check if Binary String Has at Most One Segment of Ones(1784)🚀 we need to check: The string should have only one continuous block of '1's. After a '0' appears, '1' should never appear again. ✨ Insight: Instead of manually counting segments using loops, we can simply check if "01" exists in the string. 📌 Time Complexity: O(n) Practicing problems like these helps improve pattern recognition and problem-solving efficiency. #LeetCode #DSA #Java #CodingPractice #ProblemSolving

Day: 45/365 📌 LeetCode POTD: Special Binary String Hard Key takeaways/Learnings from this problem: 1. This one teaches that recognizing a balanced structure (like valid parentheses) inside a binary string is the real trick. 2. Big takeaway: recursion + sorting substrings smartly can turn a complex greedy-looking problem into something surprisingly elegant. #POTD #365DaysOfCode #DSA #Java #ProblemSolving #LearningInPublic #Consistency 🥷

#Day39 of #365DaysOfCode Solved Set Matrix Zeroes on LeetCode. Implemented an in-place matrix approach using the first row and column as markers to track zero positions. ✨ Lesson: Smart space optimization and careful traversal help solve matrix problems efficiently. #CodingJourney #DSA #Java #LeetCode #Consistency

🚀 Day 20/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 350. Intersection of Two Arrays II Used sorting + two-pointer technique to efficiently find common elements appearing in both arrays while maintaining correct frequency. ⏱️ Time Complexity: O(n log n + m log m) 📦 Space Complexity: O(min(n, m)) (for storing the intersection) Strengthening understanding of array traversal and two-pointer pattern through consistent practice. 💪 Consistency keeps the progress moving 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency

LeetCode Problem || Prime Number of Set Bits in Binary Representation(762)🚀 Solved an interesting bit manipulation problem today! Problem : Given two integers left and right, count how many numbers in that range have a prime number of set bits (1s) in their binary representation. This problem shows how: Binary representation connects with number theory Built-in methods like bitCount() simplify bit problems Constraint analysis helps optimize thinking Small problems like this build strong fundamentals in bit manipulation. #LeetCode #Java #BitManipulation #PrimeNumbers #ProblemSolving #CodingJourney #100DaysOfCode

#day314 of #1001daysofcode problem statement (0693): Binary Number with Alternating Bits Used XOR with right shift to transform alternating bits into a sequence of 1s, then applied the (x & (x + 1)) == 0 pattern(tocheck all bits are set bits or not). Sometimes bit tricks make problems beautifully simple. #1001DaysOfCode #DSA #Java #LeetCode #ProblemSolving Shivam Mahajan #leetcode

Day: 53/365 📌 LeetCode POTD: Concatenation of Consecutive Binary Numbers Medium Key takeaways/Learnings from this problem: 1. This problem nicely mixes math + bit manipulation, especially understanding how many bits each number contributes. 2. Instead of literally concatenating strings, shifting the current result left by the bit-length is way more efficient. 3. It reinforces the idea that log2 helps you find bit length quickly for each number. 4. Big takeaway: always think in terms of binary operations when the problem screams “binary” — strings are usually a trap here. #POTD #365DaysOfCode #DSA #Java #ProblemSolving #LearningInPublic #Consistency 🥷

Leetcode Problem || Number of Steps to Reduce a Number in Binary Representation to One(1404)🚀 Today I solved a binary manipulation problem where we must: If number is even → divide by 2 If odd → add 1 Count steps until number becomes 1 💡 Learned: How to simulate binary addition using carry Avoid integer overflow Optimize string-based numeric problems #Java #DSA #BitManipulation #LeetCode #ProblemSolving