Python Ascending Order Checker

Day 25 of my #100DaysOfCode challenge 🚀 Today I worked on a Python program to check whether a list is sorted in ascending order. The goal was to verify the order of elements by comparing each element with the next one. What the program does: • Takes a list as input • Compares each element with the next element • Checks if the list follows ascending order • Returns True if sorted, otherwise False How the logic works: 1)A function is_sorted(lst) is defined 2)A loop runs from the first element to the second-last element 3)Each element is compared with the next element (lst[i] and lst[i+1]) 4)If any element is greater than the next one, the list is not sorted 5)The function immediately returns False 6)If the loop finishes without finding such a case, the function returns True Example: List 1: [1, 2, 3, 4, 5] → Sorted → True List 2: [1, 3, 2, 4, 5] → Not Sorted → False List 3: [] → Sorted → True List 4: [7] → Sorted → True Why this works well: – Only one pass through the list – Time Complexity: O(n) – Works for empty and single-element lists Key learnings from Day 25: – Sequential comparison logic – Handling edge cases in lists – Writing efficient list validation functions – Strengthening algorithmic thinking #100DaysOfCode #Day25 #Python #PythonProgramming #Algorithms #ProblemSolving #DataStructures #CodingPractice #LogicBuilding #LearnByDoing #ComputerScience #InterviewPrep #BTech #CSE #AIandML #VITBhopal #TechJourney

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