Solved LeetCode 1526: Minimum Increments to Target Array in Java

🚀 Day 140 of #150DaysOfCode on LeetCode Solved: 1526. Minimum Number of Increments on Subarrays to Form a Target Array Language: Java The task was to determine the minimum number of subarray increment operations needed to build the target array from all zeros. 🔹 Intuition: Every time the current element is greater than the previous one, it means we need that many new operations to reach the next level. Decreases don’t add extra work since earlier increments already cover them. 🔹 Approach: Start with the first element’s value as the initial count. For each subsequent element, if it’s larger than the previous one, add the difference. The sum of all such differences gives the minimum number of operations required. 🔹 Complexity: Time: O(n) Space: O(1) #LeetCode #150DaysOfCode #Java #CodingChallenge #ProblemSolving #Greedy #Arrays #DSA #TechLearning #Programmer #WomenInTech #CodeJourney #DynamicProgramming

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