Validating Binary Search Tree with Inorder Traversal

📅 Day 93 of #100DaysOfCode Problem: Palindrome Partitioning (LeetCode 131) Approach (Backtracking + Recursion): 1️⃣ Used backtracking to explore all possible substring partitions. 2️⃣ At each step, checked if the current substring is a palindrome. 3️⃣ If it is a palindrome → added it to the current path. 4️⃣ Recursively continued for the remaining substring. 5️⃣ Once we reached the end of the string → stored the valid partition. 6️⃣ Backtracked to explore other possible partitions. #100DaysOfCode #LeetCode #DSA #Backtracking #Recursion #Strings #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

Day 91 LeetCode 153: Find Minimum in Rotated Sorted Array Approach (Binary Search): 1️⃣ Used two pointers: left and right. 2️⃣ Found mid in each iteration. 3️⃣ If nums[mid] > nums[right], the minimum lies in the right half → left = mid + 1. 4️⃣ Otherwise, the minimum lies in the left half (including mid) → right = mid. 5️⃣ Continued until left == right, which gives the minimum element. Time Complexity: O(log n) Space Complexity: O(1) #100DaysOfCode #LeetCode #DSA #BinarySearch #Arrays #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

📅 Day 90 of #100DaysOfCode Problem: Find Minimum in Rotated Sorted Array (LeetCode 153) Approach (Binary Search): 1️⃣ Used two pointers: left and right. 2️⃣ Found mid in each iteration. 3️⃣ If nums[mid] > nums[right], it means the minimum lies in the right half → move left = mid + 1. 4️⃣ Otherwise, the minimum lies in the left half (including mid) → move right = mid. 5️⃣ Continued until left == right, which gives the minimum element. #100DaysOfCode #LeetCode #DSA #BinarySearch #Arrays #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

📅 Day 96 of #100DaysOfCode Problem: Rotate List (LeetCode 61) Approach (Linked List Manipulation): 1️⃣ Calculated the length of the linked list. 2️⃣ Connected the tail to the head to form a circular list. 3️⃣ Reduced rotations using k % length. 4️⃣ Found the new tail at position length - k. 5️⃣ Broke the circular link to get the new rotated list. #100DaysOfCode #LeetCode #DSA #LinkedList #Pointers #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

Leetcode potd : Sum of Root to leaf Binary Numbers Intuition : Since each node contains only 0 and 1, every root-to-leaf path naturally forms a binary number (with root as MSB). So idea is simple🌿, traverse all possible paths from root to leaf and keep building the number along the way instead of storing the full path. At every step, update the curr val so it represents the binary formed till that node. If reached the leaf node 🍃, that means one complete binary number is formed, so add to ans. So basically, it’s just dfs + building the number while moving down the tree. #leetcode #potd #problem_solving #consistency #consistency #programming

📅 Day 95 of #100DaysOfCode Problem: Path Sum (LeetCode 112) Approach (Recursion / DFS): 1️⃣ Traversed the binary tree using Depth First Search (DFS). 2️⃣ Subtracted the current node value from the target sum. 3️⃣ When reaching a leaf node, checked if remaining sum equals node value. 4️⃣ Recursively checked both left and right subtrees. 5️⃣ Returned true if any root-to-leaf path matched the target sum. #100DaysOfCode #LeetCode #DSA #BinaryTree #DFS #Recursion #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

Types of Errors Explained | Common Mistakes You Must Know Understanding errors is the first step to fixing them 💡 In this video, I explain the different types of errors in a simple and clear way. 📩 Kindly DM for the solutions. . . . . 📞 Contact Details: 📧 Email: techdremer24@gmail.com 📲 Follow & Subscribe: 🔹 Instagram: https://lnkd.in/d53Ra84a 🔹 YouTube: https://lnkd.in/dMc_Tiey #ErrorTypes #ProgrammingBasics #CodingForBeginners #StudentSupport #LearningToCode #TechDreamer #Debugging #EducationReels #Shorts #StudyHelp

🔥 Selection Sort – Code Implementation 🔥 Today I implemented Selection Sort 🧠💻 ✔️ Simple comparison-based sorting algorithm ✔️ Repeatedly selects the minimum element ✔️ Swaps it with the current index ✔️ Time Complexity: O(n²) Clean logic. Easy to understand. Great for learning sorting fundamentals. 🚀 #SelectionSort #DSA #CodingJourney #Programming #LearnToCode

📅 Day 98 of #100DaysOfCode Problem: Delete and Earn (LeetCode 740) Approach (Dynamic Programming — House Robber Pattern): 1️⃣ Converted the array into a points array where each index stores total value earned from that number. 2️⃣ Choosing a number deletes its adjacent values (num - 1 and num + 1). 3️⃣ Recognized the pattern similar to the House Robber problem. 4️⃣ At each step, decided whether to take or skip the current value. 5️⃣ Used dynamic programming to maximize total earned points. Many DP problems become easier once you recognize familiar patterns 🧠 #100DaysOfCode #LeetCode #DSA #DynamicProgramming #DP #Arrays #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

Leetcode POTD : Find Unique Binary Strings... Given an array that contains n unique binary strings, each of length n, and some possible strings are missing. Target: find a binary string of length n that is not present in the array. Thought process... Initially I thought of generating all possible binary strings of length n. Since the constraint was small, it passed all the test cases. But then I felt generating all 2^n strings just to find one missing is not really optimal, so I started thinking about a better approach 🤔 If we observe the examples carefully, we notice something interesting. There are n strings and each string has length n. Ohh yes, here is the trick 👀 Since the ansmust also be a string of length n, we can construct a new one ourselves. All the given strings are already unique, so if we flip the bit at index i from the i-th string (0 -> 1 or 1 -> 0), the newly formed string will differ from every string at least at one position. That guarantees the string will be unique and missing from the array ✨ Using this idea, the missing binary string can be found in O(n) time. #leetcode #potd #binary #strings #programming #problem_solving #consistency