LeetCode 153: Binary Search for Minimum in Rotated Sorted Array

Day 91 LeetCode 153: Find Minimum in Rotated Sorted Array Approach (Binary Search): 1️⃣ Used two pointers: left and right. 2️⃣ Found mid in each iteration. 3️⃣ If nums[mid] > nums[right], the minimum lies in the right half → left = mid + 1. 4️⃣ Otherwise, the minimum lies in the left half (including mid) → right = mid. 5️⃣ Continued until left == right, which gives the minimum element. Time Complexity: O(log n) Space Complexity: O(1) #100DaysOfCode #LeetCode #DSA #BinarySearch #Arrays #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

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