Longest Common Prefix Problem Solution

Day 47 Reverse Words in a String Today’s problem was about reversing words in a string, not characters. => Problem: Given a string, reverse the order of words while keeping each word intact. =>Approach: Split the string into words Reverse the list of words Join them back using spaces code https://lnkd.in/gV-WnTzw #DSA #Python #CodingPractice #100DaysOfCode #ProblemSolving #LeetCode #BackendDeveloper

🎯 Python | Longest Common Prefix (LeetCode) I recently solved the Longest Common Prefix problem using Python, and I’ve recorded a short video explaining the logic step by step. 🔹 Approach used: Took the first string as the initial prefix Used startswith() to compare with other strings Gradually shrunk the prefix until it matched all strings Returned the final common prefix efficiently ✅ All test cases passed ⏱️ Optimized and interview-friendly solution Sharing this as part of my continuous Python and problem-solving practice. Feedback and suggestions are always welcome! #Python #DataStructures #Algorithms #LeetCode #ProblemSolving #LearningByDoing #CodingJourney #PythonPractice

Problem Statement (leetcode 14): Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string. #dsa #strings #python #competitiveprogramming #datastructures #algorithms #codingchallenge #leetcode #dailycoder #prefix

Problem Statement (leetcode 58): Given a string s consisting of words and spaces, return the length of the last word in the string. A word is a maximal substring consisting of non-space characters only. Time complexity: O(n) Space complexity: O(n) as we use split() method to create a list of words #dsa #strings #python #competitiveprogramming #leetcode #algorithms #datastructures

LeetCode 191: Number of 1 Bits (also known as finding the Hamming Weight). The Efficiency Secret: While you can solve this using a while loop with bit-shifting or a string conversion, Python’s built-in bit_count() method is implemented directly at the C-level in the interpreter. It provides the most efficient way to count set bits in an integer. The Results: 🎯 Runtime: 0 ms (Beats 100.00%) 🧠 Memory: 17.53 MB (Beats 92.87%) This solve marks a great addition to my recent streak of 100% efficiency beats in both memory and runtime across various string and math problems. Consistency is paying off! #LeetCode #Python #BitManipulation #CleanCode #Optimization #SoftwareEngineering #Consistency

🚀 New Article: Bringing Reactive State Management to Python. I just took a deep dive into the reaktiv library. If you are looking for a type-safe, declarative way to handle state updates (without the headache of the Observer pattern), this is for you. I break down the basics of Signals and Computed values with practical code examples. 🔗 Read it here: https://lnkd.in/gY99g62M #Python #Reaktiv #Developer #ReactiveStateManagement #Library

📅 Day 01 – LeetCode Progress Update Solved LeetCode #1: Two Sum using a brute-force approach. 🔹 Logic Used Traverse the array using two nested loops Check all possible pairs to find the target sum 🔹 Why this approach? Simple and easy to understand Helpful for building strong fundamentals Good starting point before optimization 🔹 Complexity Time: O(n²) Space: O(1) 📌 Consistency over intensity—one problem, one step forward every day. #LeetCode #Day1 #Python #DSA #CodingPractice #ProblemSolving #DeveloperJourney

Daily LeetCode Progress | Day 14✅ LeetCode #3 | Longest Substring Without Repeating Characters ✔️ 🧠 Approach: • Applied a sliding window (two pointers) technique to maintain a substring with all unique characters. • Used a set to track characters in the current window for constant-time duplicate checks. • When a duplicate was encountered, shifted the left pointer until the window became valid again 🔁 • Continuously updated the maximum window size while expanding the right pointer for optimal results 📈 ⏱️ Time Complexity: O(n) 📦 Space Complexity: O(n) “Efficiency is not about doing more, it’s about doing it right.” #LeetCode #DataStructures #SlidingWindow #Python #Consistency

**Day 90: Permutation in String 🧩** Check if `s2` contains a permutation of `s1` using a **Sliding Window**! Track character counts and a `matches` variable to update the state in O(1) as you slide. No re-sorting needed, just pure O(n) efficiency! ⚡ #Day90 #SlidingWindow #LeetCode #Python #Coding #Algorithm #DSA #100DaysOfCode

Daily LeetCode Question | Day 1 ✅ LeetCode 1351: Count Negative Numbers in a Sorted Matrix ✔️ Used the two-pointer (staircase) approach starting from the top-right corner of the matrix. At each step, I leveraged the row-wise and column-wise sorted property to eliminate multiple elements at once instead of checking every cell. 🔹 Approach: Two Pointers (Staircase Search) 🔹 Time Complexity: O(m + n) 🔹 Space Complexity: O(1) This optimized approach avoids brute force and binary search, making it both efficient and interview-friendly. #LeetCode #DSA #TwoPointers #ProblemSolving #Python #CodingJourney