LeetCode 191: Counting 1 Bits with Python's bit_count() Method

If you’re duplicating fields across models, you’re doing extra work. Use Pydantic model inheritance to share validation logic cleanly. One source of truth. Less duplication. Fewer bugs. 📘 Learn scalable modelling patterns in Practical Pydantic: https://lnkd.in/eGiB7ZxU #Python #Pydantic #CleanCode

Neat Python trick objects than implement buffor protocol are internally implemented as C arrays so we can abuse memoryview to cast multidimensional arrays into flat ones like that without making copies: “memoryview(matrix).cast('B').cast('d')” Thanks to Jerry Gamashe and Frieder Erdman from AWSF slack to help figure this! #python #vfx #techart

Errors are not bugs — they’re signals. Handling them correctly is a skill ⚠️ In this Python practice, I focused on robust exception handling to make user input safer and predictable. Key concepts applied: try block to execute risky operations ValueError handling for invalid numeric input ZeroDivisionError handling to prevent runtime crashes else block to confirm successful execution finally block to ensure cleanup / final messaging runs every time This pattern mirrors real-world application behavior: Fail gracefully Inform the user clearly Never let the program crash unexpectedly Strong fundamentals like this separate hobby scripts from production-ready code 🚀 #Python #ExceptionHandling #ErrorHandling #CleanCode #LearningJourney

LeetCode Problem 28: Given two strings needle and haystack, return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. The below implementation successfully resolves this problem in time complexity of O(n) and constant space complexity. #dsa #strings #python #competitiveprogramming #leetcode #codingchallenge #optimalsolution #algorithms #twopointersalgorithm #dailycoding

Daily LeetCode Question | Day 1 ✅ LeetCode 1351: Count Negative Numbers in a Sorted Matrix ✔️ Used the two-pointer (staircase) approach starting from the top-right corner of the matrix. At each step, I leveraged the row-wise and column-wise sorted property to eliminate multiple elements at once instead of checking every cell. 🔹 Approach: Two Pointers (Staircase Search) 🔹 Time Complexity: O(m + n) 🔹 Space Complexity: O(1) This optimized approach avoids brute force and binary search, making it both efficient and interview-friendly. #LeetCode #DSA #TwoPointers #ProblemSolving #Python #CodingJourney

🚀 New Article: Bringing Reactive State Management to Python. I just took a deep dive into the reaktiv library. If you are looking for a type-safe, declarative way to handle state updates (without the headache of the Observer pattern), this is for you. I break down the basics of Signals and Computed values with practical code examples. 🔗 Read it here: https://lnkd.in/gY99g62M #Python #Reaktiv #Developer #ReactiveStateManagement #Library

**Day 90: Permutation in String 🧩** Check if `s2` contains a permutation of `s1` using a **Sliding Window**! Track character counts and a `matches` variable to update the state in O(1) as you slide. No re-sorting needed, just pure O(n) efficiency! ⚡ #Day90 #SlidingWindow #LeetCode #Python #Coding #Algorithm #DSA #100DaysOfCode

Can 40 lines of Python grow a forest? 🌳 I’ve been exploring recursive logic and randomization to create these "Live Trees" using Python's Turtle module. No two runs are ever the same. By using random.uniform for branch length and random.randint for angles, the code mimics the organic unpredictability of nature. find the code at https://lnkd.in/dkWXd6B8 Tech stack: 🐍 Python 🔢 NumPy 🎨 Turtle Graphics It’s amazing how simple math can create such complex, organic beauty. #Python #CreativeCoding #Fractals #GenerativeArt #Python

Day 35 ✅ | Check if Numbers Are Ascending in a Sentence (LeetCode 2042) Solved this string parsing problem by extracting all numbers from the sentence and verifying that they appear in strictly increasing order. A great exercise in careful parsing, integer comparison, and clean conditional logic. #Python #LeetCode #Strings #Parsing #ProblemSolving #Day35 #CodingJourney

Problem Statement (leetcode 58): Given a string s consisting of words and spaces, return the length of the last word in the string. A word is a maximal substring consisting of non-space characters only. Time complexity: O(n) Space complexity: O(n) as we use split() method to create a list of words #dsa #strings #python #competitiveprogramming #leetcode #algorithms #datastructures