Refining Linked List Skills with LeetCode Problems

🚀 Day 13 of My LeetCode Journey — Refining Linked List Skills Today’s problems: 🔹 Remove Duplicates from Sorted List (LeetCode 83) 🔹 Remove Nth Node From End of List (LeetCode 19) 💡 Problem 1: Remove Duplicates from Sorted List Since the list is already sorted: 👉 Just compare current node with next node 👉 If curr.val === curr.next.val → skip the duplicate 👉 Else → move forward Simple logic, but very effective due to the sorted property! 💡 Problem 2: Remove Nth Node From End of List Solved using two approaches: ✅ Two-Pass Approach First pass → calculate length Second pass → remove (length - n) node ⏱️ Time: O(n) ✅ One-Pass Approach (Optimized) 🔥 Use two pointers (fast & slow) Move fast ahead by n steps Move both together → when fast reaches end, slow is at target 👉 This approach is cleaner and more efficient! 🧠 What I Learned: Sorted data can simplify problems significantly Two-pointer technique continues to be super useful There’s always a way to reduce passes in linked list problems 🔥 Key Takeaways: Look for patterns (sorted, reversed, etc.) Optimize from two-pass → one-pass when possible Linked Lists are all about pointer precision Big thanks to Namaste DSA and Akshay Saini 🚀 for the guidance Day 14 loading… 💪 #LeetCode #DataStructures #Algorithms #CodingJourney #100DaysOfCode #SoftwareEngineering #Programming #InterviewPrep #JavaScript #CodingLife #TechGrowth #ProblemSolving #Developers #LearnToCode #LinkedList #TwoPointers #DSA #NamasteDSA #AkshaySaini

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