🚀 Day 11 of My LeetCode Journey — Deep Dive into Linked Lists Today was all about mastering patterns in Linked Lists: 🔹 Linked List Cycle (LeetCode 141) 🔹 Palindrome Linked List (LeetCode 234) 💡 Problem 1: Linked List Cycle Tried two approaches: ✅ Using Set Store visited nodes If node already exists → cycle detected ⏱️ Time: O(n) | 📦 Space: O(n) ✅ Fast & Slow Pointer (Floyd’s Algorithm) 🔥 Slow → 1 step Fast → 2 steps If they meet → cycle exists ⏱️ Time: O(n) | 📦 Space: O(1) 👉 This approach is elegant and optimal! 💡 Problem 2: Palindrome Linked List Again explored two approaches: ✅ Convert to Array Store values in array Compare from both ends ⏱️ Time: O(n) | 📦 Space: O(n) ✅ Optimal Approach (In-place) 🔥 Find middle node Reverse second half of linked list Compare both halves ⏱️ Time: O(n) | 📦 Space: O(1) 👉 This one really tested pointer manipulation skills! 🧠 What I Learned: One problem can have multiple valid approaches Optimal solutions often reduce space complexity Linked Lists = pointer mastery + careful thinking 🔥 Key Takeaways: Always try brute force first → then optimize Fast & slow pointer is a game-changing technique In-place solutions are highly valued in interviews Big thanks to Namaste DSA and Akshay Saini 🚀 for the guidance Day 12 loading… 💪 #LeetCode #DataStructures #Algorithms #CodingJourney #100DaysOfCode #SoftwareEngineering #Programming #InterviewPrep #JavaScript #CodingLife #TechGrowth #ProblemSolving #Developers #LearnToCode #LinkedList #TwoPointers #DSA #NamasteDSA
Mastering Linked Lists on LeetCode
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🚀 Day 12 of My LeetCode Journey — Linked List Patterns Getting Stronger Today’s problems: 🔹 Intersection of Two Linked Lists (LeetCode 160) 🔹 Remove Linked List Elements (LeetCode 203) 💡 Problem 1: Intersection of Two Linked Lists Explored two approaches: ✅ Brute Force Traverse headA and check every node in headB ⏱️ Time: O(m × n) ✅ Using Set Store all nodes of headB in a Set Traverse headA and check for intersection ⏱️ Time: O(m + n) | 📦 Space: O(n) 👉 Helped me understand how hashing can optimize comparisons. 💡 Problem 2: Remove Linked List Elements Solved using a Sentinel (Dummy) Node 🔥 👉 Create a dummy node before head 👉 Use prev pointer to skip unwanted nodes: prev.next = prev.next.next This approach simplifies edge cases like: Removing head node Multiple consecutive deletions 🧠 What I Learned: Sentinel nodes make linked list problems cleaner Hashing can reduce time complexity significantly Thinking in terms of nodes (not values) is key 🔥 Key Takeaways: Always look for ways to reduce nested loops Dummy nodes = lifesaver in linked list problems Practice is making pointer manipulation more intuitive Grateful for the guidance from Namaste DSA and Akshay Saini 🚀 Day 13 loading… 💪 #LeetCode #DataStructures #Algorithms #CodingJourney #100DaysOfCode #SoftwareEngineering #Programming #InterviewPrep #JavaScript #CodingLife #TechGrowth #ProblemSolving #Developers #LearnToCode #LinkedList #DSA #NamasteDSA #AkshaySaini
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🚀 Day 13 of My LeetCode Journey — Refining Linked List Skills Today’s problems: 🔹 Remove Duplicates from Sorted List (LeetCode 83) 🔹 Remove Nth Node From End of List (LeetCode 19) 💡 Problem 1: Remove Duplicates from Sorted List Since the list is already sorted: 👉 Just compare current node with next node 👉 If curr.val === curr.next.val → skip the duplicate 👉 Else → move forward Simple logic, but very effective due to the sorted property! 💡 Problem 2: Remove Nth Node From End of List Solved using two approaches: ✅ Two-Pass Approach First pass → calculate length Second pass → remove (length - n) node ⏱️ Time: O(n) ✅ One-Pass Approach (Optimized) 🔥 Use two pointers (fast & slow) Move fast ahead by n steps Move both together → when fast reaches end, slow is at target 👉 This approach is cleaner and more efficient! 🧠 What I Learned: Sorted data can simplify problems significantly Two-pointer technique continues to be super useful There’s always a way to reduce passes in linked list problems 🔥 Key Takeaways: Look for patterns (sorted, reversed, etc.) Optimize from two-pass → one-pass when possible Linked Lists are all about pointer precision Big thanks to Namaste DSA and Akshay Saini 🚀 for the guidance Day 14 loading… 💪 #LeetCode #DataStructures #Algorithms #CodingJourney #100DaysOfCode #SoftwareEngineering #Programming #InterviewPrep #JavaScript #CodingLife #TechGrowth #ProblemSolving #Developers #LearnToCode #LinkedList #TwoPointers #DSA #NamasteDSA #AkshaySaini
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🚀 Day 10 of My LeetCode Journey — Mastering Linked Lists Today’s problems: 🔹 Middle of the Linked List (LeetCode 876) 🔹 Reverse Linked List (LeetCode 206) 💡 Problem 1: Middle of the Linked List Used the classic slow & fast pointer approach: 👉 Slow moves 1 step 👉 Fast moves 2 steps 👉 When fast reaches the end → slow is at the middle 🎯 Such a simple trick, yet super powerful! 💡 Problem 2: Reverse Linked List This one is a must-know 🔥 👉 Iteratively reverse pointers 👉 Keep track of prev, current, and next 👉 Flip links step by step Also explored how this can be done using recursion 🧠 What I Learned: Two-pointer techniques are extremely useful Pointer manipulation builds real confidence in DSA Linked Lists are all about careful handling of references 🔥 Key Takeaways: Small tricks (like slow/fast pointers) can simplify problems a lot Practicing core problems like reversing a linked list is essential for interviews Understanding the logic > memorizing code Grateful for the learning journey with Namaste DSA and Akshay Saini 🚀 🙌 Day 11 loading… 💪 #LeetCode #DataStructures #Algorithms #CodingJourney #100DaysOfCode #SoftwareEngineering #Programming #InterviewPrep #JavaScript #CodingLife #TechGrowth #ProblemSolving #Developers #LearnToCode #LinkedList #ReverseLinkedList #TwoPointers #NamasteDSA
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🚀 Just Uploaded a New LeetCode Solution! Solved LeetCode #26 – Remove Duplicates from Sorted Array using the Two Pointer Technique in JavaScript. This is a must-know pattern for coding interviews — simple idea, but very powerful when applied correctly. 👉 In this video, I’ve covered: Intuition behind the problem Step-by-step dry run Optimal in-place solution (O(n) time, O(1) space) Clean and easy-to-understand JavaScript code 🔗 Watch here: https://lnkd.in/g-HgkGXQ If you're preparing for coding interviews or strengthening your DSA fundamentals, this one is definitely worth your time. Would love to hear your approach to this problem — drop it in the comments 👇 #leetcode #dsa #codinginterview #javascript #twopointer #programming #softwaredevelopment #coding #developers #learning #jdcodebase
Remove Duplicates from Sorted Array | Optimal Two Pointer Approach 🔥 | LeetCode Explained (JS)
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🚀 A Major Update is Coming to CodeAlive (Live in 3–4 Days!) I honestly started CodeAlive as a small platform with a simple goal in mind — to let my code snippets live over the internet with support for custom sharable links. But seeing how far it has come now, evolving into a platform with so many useful and smart features for everyone, has been incredibly exciting. 🌐 CodeAlive – https://lnkd.in/gnthhf_b 👉 Also, you can click "View My Website" on my profile to visit the platform. What’s Coming Next ⏭️ CodeAlive is soon introducing: **Multi-Language Detection & Highlighting in a Single Code File** Problem: Almost every code-sharing platforms and online editors are built around one assumption: 1 File = 1 Language But real-world development is rarely that simple. Developers often share: ✅ Frontend + Backend snippets together ✅ Embedded scripts/styles ✅ Configurations with code ✅ Multi-language examples in one paste And when platforms force a single language highlight, readability suffers. With This New Update, CodeAlive Will Support ✅ Detecting multiple languages within one pasted code file ✅ Highlighting different sections based on actual context/language ✅ Making mixed-language snippets cleaner, smarter, and easier to read This has been one of the most exciting features to work on so far, and I can’t wait to share the full implementation details once it officially goes live. 📅 Expected Release: 3–4 Days Stay tuned 👀 More technical insights coming soon... #CodeAlive #BuildInPublic #Programming #SoftwareDevelopment #DeveloperTools #WebDevelopment #Python #JavaScript #StartupJourney
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🚀 Day 24 of My Coding Journey — Power of Two Today’s problem was “Power of Two” — a simple-looking question that really highlights the beauty of bit manipulation. 🔍 What I learned: Instead of using loops or recursion, I explored how binary representation works. A power of two always has only one set bit (1) in its binary form — and that insight leads to a super efficient solution. 💡 Key trick: n & (n - 1) === 0 This removes the lowest set bit, and if the result is zero, the number is a power of two. ⚡ Takeaway: Sometimes the most optimized solutions come from understanding how data is represented internally, not just from writing more code. 📈 Progress: Day by day, I'm getting more comfortable with problem-solving patterns and thinking beyond brute force approaches. #128DaysOfCode #LeetCode #JavaScript #CodingJourney #ProblemSolving #BitManipulation
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🚀 Day 29/128 – LeetCode Challenge Today’s problem: Combination Sum (Medium) This problem was a great exercise in understanding backtracking and recursion. The goal was to find all unique combinations of numbers that add up to a target, with the twist that each number can be used multiple times. 🔍 Key Learnings: Backtracking is all about exploring possibilities and undoing choices Using a start index helps avoid duplicate combinations Recursive thinking becomes much easier with practice Important to handle base cases properly (target reached / exceeded) 💡 What clicked today: Instead of thinking “which combination is correct?”, I focused on trying every possible path and letting recursion filter valid ones. 🧠 Pattern recognized: This is a classic DFS + Backtracking problem — a pattern that shows up frequently in coding interviews. 📈 Progress update: Consistency is starting to pay off. Problems that once felt complex are becoming more intuitive. On to Day 30 🔥 #LeetCode #128DaysOfCode #DSA #CodingJourney #Backtracking #JavaScript #ProblemSolving
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🚀 Solved: Valid Parentheses (Stack Based Problem) Today I worked on a classic problem that looks simple but tests your core logic 👇 🧠 Problem: Given a string containing only (), {}, [] 👉 Check if the parentheses are valid 💡 Approach I used: Used a stack Push opening brackets For closing brackets: Check top of stack If match → pop Else → invalid ⚙️ Key Insight: 👉 Order matters more than count 👉 Stack helps track the sequence correctly 🔥 What I learned: Importance of stack in real problems Handling edge cases (empty stack, mismatch) Writing clean conditional logic 📌 Time Complexity: O(n) 📌 Space Complexity: O(n) 💬 Have you solved this problem differently? Would love to know your approach! #javascript #cpp #datastructures #algorithms #coding #leetcode #interviewprep
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I still remember the moment something clicked for me. When I first discovered I could run and submit LeetCode problems directly inside VS Code, it completely changed how I approached learning. Everything felt more immediate, more real. No switching tabs—just writing, testing, and iterating in one place. Then came that first breakthrough. I finally understood what an index really is—not just a concept, but a way to pinpoint position and control how data moves. From there, building a loop to iterate through an array and organize values started to make sense. It wasn’t just code anymore; it was logic unfolding step by step. That moment felt surprisingly familiar—like relearning something simple but foundational, the way 2 + 2 = 4 once did. Except this time, the “equation” wasn’t in plain English. It was in JavaScript. And somehow, that shift in perspective made everything more exciting. It’s wild how one small concept can unlock an entirely new way of thinking. #SoftwareEngineering #JavaScript #LeetCode #CodingJourney #VSCode
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🚀 Day 4 of my Coding Challenge Today's problem was simple but a great reminder of string fundamentals in JavaScript. Problem Statement Given a string s, return the last character of the string. Example Input: "learncoding" Output: "g" Any language Approach Use string indexing with length - 1 to access the last character. function getLastCharacter(s) { return s[s.length - 1]; } console.log(getLastCharacter("learncoding")); // g Key Learning:- Strings are index-based length - 1 always points to the last character Small problems help strengthen core programming logic Consistency matters more than complexity. One problem every day 📚 #CodingChallenge #Day4CodingChallenge #JavaScriptDeveloper #DSA #DataStructures #Algorithms #ProblemSolving #CodingJourney #CodeDaily #LearnToCode #DevelopersLife #SoftwareDeveloper #FrontendDeveloper #FullStackDeveloper #TechCommunity #ProgrammingLife #CodeNewbie #CodingPractice #DeveloperJourney #CodingSkills #TechLearning #JavaScriptCoding #WebDeveloper #ProgrammingChallenge #DailyCoding #CodeMotivation #CareerInTech #DeveloperMindset #CodingGrind #TechGrowth
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