Dynamic Programming for Longest Increasing Subsequence

🚀 DSA Deep Dive – Day 30 Solved Longest Increasing Subsequence today. And I realized… Dynamic Programming is not about continuous subarrays. It’s about controlled choices over time. 🤯 The problem sounds simple: Given an array, find the length of the longest strictly increasing subsequence. Not subarray. Subsequence. That one word changes everything. 👀 You’re allowed to skip elements. But you must maintain order. Here’s what I learned 👇 • Define dp[i] = length of LIS ending at index i • Every element can start a subsequence (minimum length = 1) • For every i, check all j < i • If nums[j] < nums[i] → extend subsequence • Take the maximum possible extension This is classic DP state building. At every index, you ask: 👉 Can I extend a previous increasing chain? 👉 Or do I start fresh from here? Brute force recursion: Exponential 💀 Optimized DP (nested loops): O(n²) ⚡ Even better approach exists: O(n log n) with binary search 🚀 But the mindset is what matters. The powerful shift? Instead of asking “What is the longest sequence overall?” Ask “What is the longest sequence ending HERE?” That’s dynamic programming thinking. Local decisions → Global answer. Lesson: DP is not about memorizing patterns. It’s about defining the right state. Once the state is clear, the transition becomes obvious. 30 days in. Graphs ✅ 1-D DP almost done 🚀 Consistency compounds. Follow for more DSA breakdowns 🔥 #LeetCode #DSA #DynamicProgramming #InterviewPrep #CodingJourney #ProblemSolving #100DaysOfCode #SoftwareEngineering #TechGrowth

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