Dynamic Programming: Interleaving Strings with DP Grid

🚀 DSA Deep Dive – Day 36 Solved Interleaving String today. And I realized… Dynamic Programming is not about combining strings. It’s about validating paths. 🤯 The problem looks simple: Given 3 strings s1, s2, s3 Check if s3 is formed by interleaving s1 and s2. Sounds like string matching… 👀 But it’s actually a 2D decision problem. Here’s what I learned 👇 • Total length must match: 👉 s1.length + s2.length == s3.length • Define dp[i][j] = Can we form s3[0…i+j-1] using: 👉 s1[0…i-1] and s2[0…j-1] • Two choices at every step: 👉 Take character from s1 👉 Take character from s2 Transitions: • If s1[i-1] == s3[i+j-1] → check dp[i-1][j] • If s2[j-1] == s3[i+j-1] → check dp[i][j-1] If any is true → dp[i][j] = true ✅ Brute force recursion: Exponential 💀 Optimized DP: O(n × m) ⚡ Space optimized possible 🚀 The powerful shift? Instead of asking “Can I build s3 completely?” Ask “Can I reach THIS position using prefixes of s1 and s2?” Step-by-step validation → final answer. Lesson: Many string problems are actually DP grid problems. Think in terms of positions. Think in terms of choices. That’s where clarity comes. DP intuition leveling up 💪 Consistency continues. Follow for more DSA breakdowns 🚀 #LeetCode #DSA #DynamicProgramming #InterviewPrep #CodingJourney #ProblemSolving #100DaysOfCode #SoftwareEngineering #TechGrowth

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