Java Next Permutation Solution

🚀 DSA Learning Journey | Day 4 | Java Solved “Kth Largest Element in an Array.” 💡 Key Idea: Used the Heap / Priority Queue approach to efficiently find the Kth largest element without fully sorting the array. ⚙ Implementation • Language: Java • Time Complexity: O(n log k) • Space Complexity: O(k) 📚 Learning how heaps help optimize selection problems in arrays. #Java #DSA #LeetCode #ProblemSolving #JavaDeveloper #Algorithms

🚀 DSA Learning Journey | Day 7 | Java Solved “Single Number.” 💡 Key Idea: Used Bit Manipulation (XOR) — identical numbers cancel out, leaving the unique element. ⚙ Implementation • Language: Java • Time Complexity: O(n) • Space Complexity: O(1) 📚 Learning how XOR helps solve problems efficiently without extra space. #Java #DSA #LeetCode #ProblemSolving #BitManipulation #JavaDeveloper

🚀 DSA Learning Journey | Day 2 | Java Solved “Search in Rotated Sorted Array.” 💡 Key Idea: Applied Binary Search by determining which half of the array is sorted and narrowing the search space. ⚙ Implementation • Language: Java • Time Complexity: O(log n) • Space Complexity: O(1) 📚 Learning how binary search can be adapted to work with rotated sorted arrays. #Java #DSA #LeetCode #ProblemSolving #BinarySearch #JavaDeveloper

🚀 DSA Learning Journey | Day 9 | Java Solved “125. Valid Palindrome.” 💡 Key Idea: Used Two Pointers while ignoring non-alphanumeric characters and comparing characters in a case-insensitive way. ⚙ Implementation • Language: Java • Time Complexity: O(n) • Space Complexity: O(1) 📚 Learning how two-pointer technique simplifies string validation problems. #Java #DSA #LeetCode #ProblemSolving #TwoPointers #JavaDeveloper

🚀 DSA Learning Journey | Day 5 | Java Solved “Maximum Product Subarray.” 💡 Key Idea: Tracked both maximum and minimum products at each step since a negative number can flip the sign and turn a minimum into a maximum. ⚙ Implementation • Language: Java • Time Complexity: O(n) • Space Complexity: O(1) 📚 Learning how handling negative numbers and dynamic updates is important in product-based subarray problems. #Java #DSA #LeetCode #ProblemSolving #JavaDeveloper #Algorithms

🚀 Day 33 / 180 – DSA with Java 🚀 📘 Topic Covered: Arrays & Index Manipulation 🧩 Problem Solved: Shuffle the Array Problem: Given an array in the form [x1, x2, ..., xn, y1, y2, ..., yn], rearrange it to [x1, y1, x2, y2, ..., xn, yn]. Approach: Used two pointers to track elements from the first and second halves of the array, then alternately placed them into a new array to achieve the required shuffle pattern. Key Learning: ✔️ Managing multiple pointers in array problems ✔️ Practicing index-based rearrangement ✔️ Maintaining correct ordering while constructing a new array If you’re also preparing for DSA, let’s connect and learn together 🤝 #DSA #Java #180DaysOfCode #LearningInPublic #Arrays #ProblemSolving #Consistency

Day 46 of #100DaysOfLeetCode 💻✅ Solved #374. Guess Number Higher or Lower problem in Java. Approach: • Used Binary Search to efficiently guess the number. • Calculated mid using low + (high - low) / 2 to avoid overflow. • Used the guess(mid) API to check if the number is higher, lower, or correct. • Updated the search range accordingly until the number was found. Performance: ✓ Runtime: 0 ms (Beats 100% submissions) 🚀 ✓ Memory: 41.68 MB (Beats 97.84% submissions) Key Learning: ✓ Practiced implementing binary search on a real problem ✓ Learned how to safely calculate mid to prevent integer overflow ✓ Strengthened problem-solving skills with search algorithms Learning one problem every single day 🚀 #Java #LeetCode #DSA #BinarySearch #ProblemSolving #CodingJourney #100DaysOfCode

🚀 DSA Learning Journey | Day 6 | Java Solved “Find Minimum in Rotated Sorted Array.” 💡 Key Idea: Used Binary Search to locate the pivot point where the rotation happens and identify the minimum element efficiently. ⚙ Implementation • Language: Java • Time Complexity: O(log n) • Space Complexity: O(1) 📚 Learning how binary search can be applied to modified sorted arrays. #Java #DSA #LeetCode #ProblemSolving #BinarySearch #JavaDeveloper #day6

🚀 Day 34 / 180 – DSA with Java 🚀 📘 Topic Covered: Arrays & Basic Construction 🧩 Problem Solved: Concatenation of Array Problem: Given an integer array nums, create a new array that contains the elements of nums twice in sequence. Approach: Created a new array with double the size of the original array and filled the first half with the original elements, then copied the same elements again into the second half. Key Learning: ✔️ Practicing array construction and indexing ✔️ Understanding how to manipulate array sizes ✔️ Writing clean logic for simple transformation problems If you’re also preparing for DSA, let’s connect and learn together 🤝 #DSA #Java #180DaysOfCode #LearningInPublic #Arrays #ProblemSolving #Consistency 

💻 Practicing Binary to Decimal Conversion using Java Today I worked on converting a binary number into its decimal equivalent using logic and iteration. 🔍 Key Learnings: Understanding how binary digits map to powers of 2 Strengthening loop and mathematical logic Improving problem-solving skills step by step Instead of just memorizing, I focused on understanding the logic deeply and practicing with different inputs. 📌 Example: Binary: 1010 → Decimal: 10 Consistency + Practice = Progress 🚀 #Java #DSA #CodingJourney #Programming #100DaysOfCode #LearnToCode #ProblemSolving #DeveloperJourney #CodingPractice #TechSkills