Vishal Balasubramanian’s Post

LeetCode Progress | 242. Valid Anagram (Python) Today I solved “Valid Anagram” on LeetCode. Problem: Given two strings s and t, return True if t is an anagram of s, otherwise return False. My approach: I compared character frequencies between the two strings. -- Created a set of characters from the longer string -- For each character, compared its count in both strings -- If any frequency differed, returned False Optimal approach: A more efficient solution uses frequency counting. -- Use a hash map (dictionary) or fixed-size array (26 characters) -- Increment counts for s and decrement for t -- If all counts are zero, the strings are anagrams This avoids repeated count() calls and improves performance. Follow-up (Unicode characters): -- A dictionary-based frequency counter works well for Unicode -- Arrays are less suitable because the character set is not fixed What I learned: -- Repeated counting inside loops increases time complexity -- Choosing the right data structure can significantly improve efficiency -- Frequency-based problems often have cleaner linear-time solutions #leetcode #python #dsa #datastructures #algorithms #coding #programming #problemSolving #softwareengineering #computerscience #interviewprep #codinginterview #100daysofcode #pythonprogramming

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