Four Divisors Sum with √n Optimization

🗓 Day 61 / 100 – #100DaysOfLeetCode 📌 Problem 1390: Four Divisors Today’s problem combined number theory fundamentals with careful iteration. The task was to scan through an array and compute the sum of divisors only for those numbers that have exactly four distinct divisors. 🧠 My Approach: For each number in the array: Iterated from 1 to √x to find divisor pairs efficiently. Whenever i divides x, added both i and x / i to a set to ensure uniqueness. Accumulated the sum of these divisors while tracking how many unique divisors were found. After processing a number, checked: If it had exactly 4 divisors, added its divisor sum to the final answer. Otherwise, ignored it. Using the square-root optimization keeps the solution efficient even for large values. 💡 Key Learning: This problem reinforced: ✔ efficient divisor enumeration using √n optimization ✔ using sets to avoid duplicate divisors ✔ applying number theory concepts in coding problems ✔ filtering results based on strict conditions A solid reminder that understanding divisor patterns can simplify many math-based problems in DSA 🚀 #100DaysOfLeetCode #LeetCodeChallenge #Python #ProblemSolving #Math #NumberTheory #Divisors #Algorithms #DSA #CompetitiveProgramming #SoftwareEngineering #CodingJourney #DeveloperJourney #LearningInPublic #TechStudent #CareerGrowth #Programming #KeepLearning

  • graphical user interface, application

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