Python Performance Analysis with Profiling-Explorer

C++26 Reflection & Python Bindings Writing bindings manually is tedious: * Extra code you need to read, maintain(,and write). * Extra dependencies in the project. * Extra bugs. I’ve been exploring C++26 reflection and built a small prototype: automatic Python bindings without writing bindings. Here’s how it works 👇 Post: https://lnkd.in/gwJYhnnF Code: https://lnkd.in/gbQqPVNr #cpp #reflection #c++26

Python Dunder Methods: Making code more "Pythonic" 🐍 I’ve been playing around with operator overloading today! Instead of writing a bulky function like add_packages(pkg1, pkg2), Python allows us to use the __add__ magic method. By defining __add__, I can simply use the + operator to combine two package objects. Cleaner syntax? Check. More readable? Absolutely. I also added __str__ to ensure that when I print the result, I get a clear, formatted summary of the dimensions and weight rather than a messy memory address. #Python #CodingTips #SoftwareDevelopment #ObjectOrientedProgramming #CleanCode

My current mental model when building with agents: Python --> Agentic harness (eg Claude Code) Class --> Domain specific agent that orchestrates Function --> Task specific subagent Utility Functions --> Agent skills Script Logs --> Agent state logs The former being used for deterministic tasks, and the latter leveraging the former for non-deterministic tasks.

🚀 Day 27 of Python Problem Solving!! Today, I worked on the classic Two Sum problem. 💡 What I Practiced Today: Traversing arrays using loops Understanding brute force vs optimized approaches Using hashmaps (dictionaries) for faster lookups Improving time complexity from O(n²) to O(n) Writing clean and efficient Python code 🧠 Problem Statement: Given an array of integers nums and an integer target, return the indices i and j such that: nums[i] + nums[j] == target and i != j. 📌 Example: Input: nums = [2, 7, 11, 15], target = 9 Output: [0, 1] ✨ I explored two approaches: 1️⃣ Brute Force using nested loops (O(n²)) 2️⃣ Optimized approach using a dictionary for constant-time lookup (O(n)) This problem helped me understand how choosing the right data structure can significantly improve performance — an important concept for coding interviews. #Day27 #100DaysOfCode #Python #CodingJourney #ProblemSolving #DataStructures #Programming #LearnToCode #TechJourney

Shiny for Python 1.6 is out on PyPI! Download or upgrade and play with some great new features, including toolbar components and OpenTelemetry integration! https://lnkd.in/gPw3Zk8g

Here’s a tiny Python change that pays off fast. Python tip: use `@dataclass(slots=True)` for high-volume models. It removes per-instance `__dict__`, which usually means lower memory usage and slightly faster attribute access. Great for DTOs, parser outputs, event payloads, and cache objects where shape is fixed. Mini rule: if the object schema is stable, add `slots=True` by default. #Python #Performance #CodeQuality #SoftwareEngineering

Tiny Python upgrade for cleaner analytics code: Use Counter instead of manual dict increments. You get frequency maps in one pass and top-N insights with most_common(). Less boilerplate, fewer mistakes, faster review. Mini pattern: - counts = Counter(values) - top = counts.most_common(3) - act on thresholds #Python #CodingTips #Backend #DevTips #SoftwareEngineering

Fun Python 4/100 X=“Akashvi“ if X == “Akash” or “Asma”: print (“ True”) else: print (“ False”) what will be the output ?

Python Challenge – Can you solve this? Today was all about deep-diving into Lists vs. Sets and I came across a common mistake that we can sometimes overlook. Let’s test your Python understanding👇 numbers = [1, 2, 3] numbers.append([4, 5]) print(len(numbers)) A) 3 B) 4 C) 5 D) Error It’s a classic interview question that tests if you truly understand how Python handles memory and lists. Day 15/30 #30DaysOfCode #DataStructures #Day15 #PythonQuiz

Day 55/100 – #100DaysOfCode 🚀 Solved LeetCode #205 – Isomorphic Strings (Python). Today I practiced hashmap (dictionary) usage to check whether two strings follow the same pattern. Approach: 1) Create two hashmaps to store character mappings in both directions. 2) Traverse both strings together using zip(). 3) Check if the current mapping is consistent in both maps. 4) If any mismatch is found, return False. 5) Otherwise, update the mappings and continue. 6) If all mappings are valid, return True. Time Complexity: O(n) Space Complexity: O(n) Understanding how bidirectional mapping ensures consistency 💪 #LeetCode #Python #DSA #HashMap #Strings #ProblemSolving #100DaysOfCode