Java Functional Interfaces Simplified with Lambda Expressions

🚀Understanding @#Autowired in #SpringFramework Today I learned about @Autowired in the Spring Framework. 🔎 @Autowired is used for automatic dependency injection. It tells the Spring Container to automatically inject the required bean. Instead of creating objects manually using new, Spring automatically connects the required dependencies. 📌 Example: @Component public class StudentService { @Autowired private StudentRepository repository; } This helps reduce boilerplate code and makes applications loosely coupled. #SpringFramework #Java #BackendDevelopment #SpringBoot #LearningJourney 10000 Coders Understanding @Autowired Annotation Content: Automatic Dependency Injection Spring injects required beans automatically Reduces manual object creation

⏰ Temporary Field: When instance variables only show up for certain operations, cluttering your class interface with null-initialized fields. Here's how Extract Class refactoring transforms your code: ✅ Move temporary fields into dedicated classes ✅ Eliminate null-initialized field clutter ✅ Create clearer class interfaces ✅ Make object state predictable at every stage 🎯 Key takeaway: Extract Class refactoring organizes temporary state into focused objects that only exist when they're needed. What's your experience with refactoring Temporary Fields? Share your favorite techniques in the comments. #CleanCode #Refactoring #Java #TemporaryField #DeveloperTips https://lnkd.in/gJQeWPJ9

Day 20-What I Learned In a Day(JAVA) What is Method? A method is a block of code that performs a specific task. It is used to improve code reusability, readability, and modularity. Syntax: accessModifierreturnTypemethodName(parameters) { // method body } Important Terminologies: 1️⃣ Method Signature Method name + parameter list only. Example: add(int, int) (It does NOT include return type.) 2️⃣ Method Declaration Return type + method name + parameters (without body). Example: public int add(int a, int b); 3️⃣ Method Definition Complete method including body (implementation). Example: public int add(int a, int b) { return a + b; }  Practice Done Today ✔ Created methods for addition, subtraction, multiplication,Division ✔ Understood static and non-static methods ✔ Practiced method calling ✔ Practiced dynamic input using Scanner Practiced 👇 #Java #CoreJava #JavaMethods #MethodSignature #MethodDeclaration #MethodDefinition #StaticVsNonStatic #OOPSConcepts #JavaBasics #CodingPractice #LearningJourney

Today’s challenge was all about logic and boundary management. Solving the Spiral Matrix in Java isn't just about the code; it’s about visualizing how to traverse a 2D array while keeping track of four changing boundaries (top, bottom, left, right). It’s easy to get lost in the indices, but once the logic clicks, it feels like magic. These are the kinds of problems that sharpen the mind for the rigorous interviews at companies like Google and Microsoft. One step closer to the goal! 🚀 #DSA #Java #CodingJourney #SpiralMatrix #ProblemSolving #SoftwareEngineer #DataStructures #Algorithms

🔥 Day 98 of #100DaysOfCode Today’s challenge: LeetCode – Search in Rotated Sorted Array II 🔄🔍 📌 Problem Summary You are given a rotated sorted array that may contain duplicates. Your task is to determine whether a target exists in the array. Example: Input: nums = [2,5,6,0,0,1,2], target = 0 Output: true 🧠 Approach Used: Linear Search In this implementation, we simply iterate through the array and check if the element matches the target. ⚙️ Logic for(int i = 0; i < nums.length; i++){ if(nums[i] == target){ return true; } } return false; 💡 Explanation Traverse the array from start to end If the target is found → return true If the loop finishes → return false ⏱ Time Complexity: O(n) 💾 Space Complexity: O(1) 🚀 Performance Runtime: 0 ms Memory: 44.9 MB 🧠 Learning This problem is a variation of Search in Rotated Sorted Array, but with duplicates allowed. While a Binary Search solution exists, duplicates can break the strict ordering and make the logic more complex. A simple linear scan ensures correctness in all cases. Only 2 days left to complete #100DaysOfCode 🚀 Almost at the finish line! On to Day 99 🔥 #100DaysOfCode #LeetCode #Java #DSA #CodingJourney #InterviewPrep

Day 8 Today I solved “Check if Binary String Has at Most One Segment of Ones” on LeetCode. At first glance, the problem looks simple: Given a binary string, check whether it contains only one continuous segment of '1's. Example: "110" → Valid (one segment of 1s) "1001" → Invalid (two separate segments of 1s) While solving it, I realized an interesting observation: 👉 If a binary string has more than one segment of 1s, the pattern "01" must appear before another "1". So instead of counting segments explicitly, we can simply check whether '01' appears and is followed by another '1'. This turns the problem into a very efficient linear scan with O(n) time complexity. 💡 Key takeaway: Sometimes the simplest solution comes from recognizing patterns in the string rather than simulating the whole process. Also happy to see my solution running at 0 ms runtime (100% faster) 🚀 #LeetCode #DSA #ProblemSolving #Java #CodingJourney #BinaryStrings

DSA daily streak | day-35 ✅ Sum of Two Integers Today, I explored how to add two integers without using the + or - operators. This problem dives into bit manipulation and how addition works at the binary level. #DSA #Java #ProblemSolving #LeetCode #SlidingWindow #Algorithms #CodingJourney #LearningJourney

🚀 POTD Completed – Push Zeros To End (Java) Consistency is starting to show results 💯 Today’s Problem of the Day was all about optimizing array manipulation by pushing all zeros to the end while maintaining the order of non-zero elements. 🔹 Approach I Used: Instead of using extra space, I focused on an in-place solution. 1️⃣ Traverse the array 2️⃣ Maintain an index (idx) for placing non-zero elements 3️⃣ Copy all non-zero elements forward 4️⃣ Fill the remaining positions with zeros This ensures: ✔️ Time Complexity: O(n) ✔️ Space Complexity: O(1) 💡 Key Insight: The idea is not to “move zeros”, but to “shift non-zeros forward efficiently”. 🔥 Result: ✅ 1115 / 1115 test cases passed ✅ 100% accuracy ✅ Clean and optimal solution Every small problem solved builds stronger logic and confidence. Day by day, step by step — getting closer to mastering DSA 🚀 #DSA #Java #ProblemOfTheDay #CodingJourney #Consistency #LeetCode #Programming

🚀 #60DaysOfLeetCode – Day 32 Today’s problem was about removing all adjacent duplicates in a string. 🔹 Approach Used: Stack To efficiently handle consecutive duplicates, I used a stack-based approach: Traverse the string character by character. If the stack is not empty and the top element matches the current character, pop it (this removes the duplicate pair). Otherwise, push the current character onto the stack. Finally, build the result string from the stack and reverse it to maintain the correct order. 🔹 Key Learning: Using a stack helps simulate the process of removing adjacent duplicates in a single pass, achieving O(n) time complexity and avoiding unnecessary reprocessing. This problem highlights how stacks are powerful for handling sequential patterns and cancellations, especially in string manipulation problems. On to Day 33! 💻🔥 #LeetCode #DSA #Java #CodingChallenge #ProblemSolving #LearningInPublic #60DaysOfCode

🚀 Day 38 of #100DaysOfLeetCode Today I solved "Container With Most Water" problem on LeetCode. 🔹 Difficulty: Medium 🔹 Concept Used: Two Pointer Technique 🔹 Language: Java 📌 Problem Summary: Given an array representing heights of vertical lines, the goal is to find two lines that together with the x-axis can contain the maximum amount of water. 💡 Approach: Instead of checking all possible pairs (O(n²)), I used the Two Pointer approach which reduces the time complexity to O(n). Steps: 1️⃣ Start with two pointers at the beginning and end of the array. 2️⃣ Calculate the area using the smaller height. 3️⃣ Move the pointer with the smaller height inward. 4️⃣ Track the maximum area during each step. 📊 Result: ✅ Runtime: 5 ms (Beats 81.86%) ✅ Memory: Beats 95.54% This problem was a great exercise to understand optimization using two pointers instead of brute force. Consistency is the key — moving forward one problem at a time! 💪 #LeetCode #100DaysOfCode #Java #DSA #CodingChallenge #ProblemSolving #SoftwareEngineering