Checking if a List Is a Palindrome in Python

Day 12/365: Checking If a List Is a Palindrome in Python 🔁 Today I solved a classic problem in Python: checking whether a list is a palindrome or not — using the two‑pointer technique with a for-else loop. 🔍 How this works step by step: I start with a list l that has elements arranged symmetrically. To check if it’s a palindrome, I compare elements from both ends: l[0] with l[-1], l[1] with l[-2], and so on. I only need to go till the middle of the list: range(len(l)//2) Inside the loop: If any pair doesn’t match, I print "list is not palindrome" and use break to exit the loop early. The interesting part is the for-else: The else block runs only if the loop finishes without hitting a break. That means all pairs matched, so I print "list is palindrome". 💡 What I learned: How to use the two‑pointer technique to compare elements from start and end efficiently. How Python’s for-else works — the else is tied to the loop, not the if. Why we only need to iterate till the middle of the list for palindrome checking. How the same logic can be reused for: checking if a string is a palindrome, validating symmetric data in lists and arrays. Day 12 done ✅ 353 more to go. If you have ideas like: checking palindromes while ignoring cases/spaces in strings, handling mixed data types in lists, or checking palindromes in other data structures, drop them in the comments — I’d love to try them next. #100DaysOfCode #365DaysOfCode #Python #LogicBuilding #TwoPointers #Lists #CodingJourney #LearnInPublic #AspiringDeveloper

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