Rebuilding Array.filter() in JavaScript

🚀 Day 8 / 30 - JavaScript Coding Practice Today’s challenge: Rebuilding Array.filter() without using the built-in method 👀 Problem: Given an integer array arr and a filtering function fn, return a filtered array filteredArr. The fn function takes one or two arguments: arr[i] - number from the arr i - index of arr[i] filteredArr should only contain the elements from the arr for which the expression fn(arr[i], i) evaluates to a truthy value. A truthy value is a value where Boolean(value) returns true. Please solve it without the built-in Array.filter method.   Example 1: Input: arr = [0,10,20,30], fn = function greaterThan10(n) { return n > 10; } Output: [20,30] Explanation: const newArray = filter(arr, fn); // [20, 30] The function filters out values that are not greater than 10 Example 2: Input: arr = [1,2,3], fn = function firstIndex(n, i) { return i === 0; } Output: [1] Explanation: fn can also accept the index of each element In this case, the function removes elements not at index 0 Example 3: Input: arr = [-2,-1,0,1,2], fn = function plusOne(n) { return n + 1 } Output: [-2,0,1,2] Explanation: Falsey values such as 0 should be filtered out Solution: var filter = function (arr, fn) {     let formattedArr = [];     for (let i = 0; i < arr.length; i++) {         if (fn(arr[i], i)) {             formattedArr.push(arr[i]);         }     }     return formattedArr; }; #JavaScript #DSA #CodingPractice #100DaysOfCode #FrontendDevelopment #ProblemSolving

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