"Removing Duplicates from Sorted Linked List in O(n) Time"

🔍 Day 22/50 | Back to Basics — The Beauty of Understanding Deeply Today’s focus: “Remove Duplicates from Sorted List” — a deceptively simple linked list problem that taught me once again that clarity beats complexity. 💡 The Problem: Given the head of a sorted linked list, delete all duplicates so that each element appears only once — while keeping the list sorted. 🎯 The Approach: When lists are sorted, duplicates are always neighbors. So instead of extra storage, we can simply traverse once and skip duplicates in place. Steps: 1️⃣ Start from the head 2️⃣ Compare each node’s value with the next 3️⃣ If equal → skip the next node 4️⃣ Else → move forward Elegant. Clean. Linear. ⚡ Complexity: ✅ Time: O(n) — Single pass through the list ✅ Space: O(1) — No extra memory 📚 Why This Problem Matters: After a week of exploring search-based and array problems, this one grounded me again — reminding me: 1️⃣ “Easy” problems are never trivial — they test your logic discipline. 2️⃣ Linked lists are where pointer logic meets patience. 3️⃣ Writing clean, bug-free code is the real challenge — not syntax, but structure. 🔑 Key Takeaway: Mastering fundamentals isn’t repetition — it’s refinement. Every revisit to basics strengthens your grip on clarity, logic, and flow. 🧠 Day 22/50 ✅ | Simplify, don’t overcomplicate.Shishir chaurasiya and PrepInsta #50DaysOfCode #LeetCode #CodingJourney #ProblemSolving #LinkedList #DSA #Algorithms #CPlusPlus #Python #SoftwareEngineering #TechJourney #BackToBasics #LearningInPublic #CodeAndGrow #DeveloperLife #Consistency

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