LeetCode Challenge Day 13: Binary Search & Math Optimization

🚀 Day 13 of 100 Days LeetCode Challenge Problem: Minimum Number of Seconds to Make Mountain Height Zero Today’s problem was a strong mix of Binary Search + Mathematical Optimization 🔥 💡 Key Insight: Each worker takes time in an increasing pattern: For x units of work → time = t * (1 + 2 + ... + x) = t * x(x+1)/2 👉 This converts the problem into: “Given time T, how much total work can all workers complete?” 🔍 Core Approach: 1️⃣ Binary Search on Time (Answer) Guess a time T Check if all workers together can reduce height ≥ mountainHeight 2️⃣ For Each Worker: Solve: t * x(x+1)/2 ≤ T Find maximum x using math / binary search 3️⃣ Sum all x values If total ≥ required height → ✅ possible 🔥 What I Learned Today: Converting real-world problems into mathematical formulas is powerful Binary Search is not just for arrays—it works on answers too Combining math + search = efficient solution 📈 Challenge Progress: Day 13/100 ✅ Getting stronger every day! LeetCode, Binary Search, Mathematical Optimization, Greedy, Algorithms, DSA Practice, Coding Challenge, Problem Solving #100DaysOfCode #LeetCode #DSA #CodingChallenge #BinarySearch #Mathematics #Optimization #ProblemSolving #TechJourney #ProgrammerLife #SoftwareDeveloper #CodingLife #LearnToCode #Developers #Consistency #GrowthMindset #InterviewPrep

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