Why char occupies 2 bytes in Java but 1 byte in C

💡 Why char Occupies 2 Bytes in Java but 1 Byte in C💡 Many learners get confused about why char takes 2 bytes in Java while it takes only 1 byte in C. Let’s understand it simply ⚙️ In C (1 Byte) 🔸C is a low-level, hardware-oriented language. 🔸The size of char in C is defined as 1 byte, which is typically 8 bits on modern systems. 🔸C was created when systems mainly used ASCII, so one byte (0–255) was enough to represent characters. The exact number of bits per char may vary depending on the system (for example, 8, 9, or even 16 in rare architectures). ☕ In Java (2 Bytes) 🔸Java was designed with Unicode (UTF-16) support to handle multiple languages and symbols worldwide 🌍. 🔸Hence, every char in Java occupies 16 bits (2 bytes) — enough to represent most Unicode characters. 🔸Java ensures portability — meaning a character uses the same memory size on every platform. ✨ In Short 🔸Java → 2 Bytes for global Unicode 🌏 🔸C → 1 Byte for hardware efficiency ⚙️ 🔸Java focuses on portability and internationalization, 🔸C focuses on speed and direct hardware control 💻 📘 Conclusion Both languages made the right choice for their time and purpose. 🔸Java wanted “write once, run anywhere” 🌐 🔸C wanted “run fast, close to the machine” ⚡ #Java #C #Programming #Coding #Unicode #JVM #LearnToCode #CodeSmart #ComputerScience #Codegnan Thanks to my mentor Anand Kumar Buddarapu Saketh Kallepu Uppugundla Sairam

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