Optimized Longest Increasing Subsequence in Java with Binary Search

🚀 Daily DSA Practice – Day 63 | Dynamic Programming – Longest Increasing Subsequence (Optimized) (Java) Continuing my DSA journey, today I revisited a classic problem with an optimized approach, improving time complexity significantly. 📌 Problem Solved (LeetCode): 300. Longest Increasing Subsequence (Medium) 🎯 Concept: Binary Search + Dynamic Programming Optimization 🧠 Problem Idea: Previously, I solved LIS using O(n²) DP. Today, I learned the optimized O(n log n) approach using Binary Search. Instead of storing all subsequences, we maintain a list where: Each index represents the smallest possible tail of an increasing subsequence of that length Logic If current element > last → append Else → replace using binary search 🔍 What I Practiced: ✔ Optimizing DP from O(n²) → O(n log n) ✔ Applying binary search in DP problems ✔ Understanding greedy + DP hybrid approach ✔ Improving performance for large input constraints This problem taught me how optimization techniques can make a huge difference in efficiency, which is critical in coding interviews. #DSA #LeetCode #DynamicProgramming #Java #BinarySearch #ProblemSolving #InterviewPreparation #Consistenc

To view or add a comment, sign in

Explore content categories