"LeetCode Challenge: Counting Laser Beams in a Bank with Python"

🔐 LeetCode Problem #2125: Number of Laser Beams in a Bank Today’s Python challenge focuses on optimizing logic and pattern recognition in a matrix-based problem involving laser beams between security devices in a bank. 📄 Problem Summary: You are given a list of binary strings representing the floor plan of a bank. '1' → A security device '0' → An empty cell There is one laser beam between any two devices if: They are on different rows (r1 < r2), and Every row between them has no devices ('0's only). The task is to calculate the total number of laser beams in the bank. 🧠 Key Python Concepts Used: String Counting: Using row.count('1') to efficiently count devices in each row. Filtering Non-Empty Rows: Skipping rows without devices to reduce unnecessary computation. Mathematical Pattern Recognition: Realizing that beams only form between consecutive non-empty rows, allowing a simple multiplication-based approach. 📊 Example: bank = ["011001", "000000", "010100", "001000"] # Output: 8 Explanation: Devices per row: [3, 0, 2, 1] → Filtered: [3, 2, 1] Beams = (3×2) + (2×1) = 8 ⏱️ Complexity: Time: O(m × n) — count devices per row once. Space: O(m) — store counts for non-empty rows. 💡 Learning: This problem highlights the importance of: Recognizing patterns that simplify complex iteration. Transforming multi-layered conditions into clean, sequential logic. Writing readable and efficient Python code using list comprehensions and clean iteration. A great exercise in algorithmic optimization and elegant problem solving! 🧩 #Python #LeetCode #ProblemSolving #DataScience

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