LeetCode 2839: Check if Strings Can Be Made Equal

🚀 Day 48/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 1534. Count Good Triplets Used a brute-force triple nested loop to check all possible triplets and validate the given conditions using absolute differences. ⏱️ Time Complexity: O(n³) 📦 Space Complexity: O(1) Strengthening understanding of nested loop patterns and condition-based filtering. 💪 Consistency continues 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency

Solved a problem where we need to check if two strings can be made equal using a special operation. The rule is: you can swap characters only if the distance between their positions is even. So basically, characters at even indices can only swap among themselves, and same for odd indices. Idea: Instead of actually swapping, I just counted characters separately for even and odd positions in both strings. If both match, then it’s possible — otherwise not. Simple concept, but interesting twist! 😊 #LeetCode #DSA #Java #ProblemSolving #CodingJourney

🚀 Day 65/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 2535. Difference Between Element Sum and Digit Sum of an Array Used a single loop + digit extraction approach to calculate both element sum and digit sum efficiently. ⏱️ Time Complexity: O(n × d) 📦 Space Complexity: O(1) Strengthening understanding of number manipulation and digit-based operations. 💪 Consistency continues 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency

🚀 Day 47/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 448. Find All Numbers Disappeared in an Array Used an in-place marking technique by treating indices as a hash map and marking visited numbers as negative to identify missing elements. ⏱️ Time Complexity: O(n) 📦 Space Complexity: O(1) (excluding output list) Strengthening understanding of array manipulation and in-place hashing tricks. 💪 Consistency continues 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency

🚀 Day 69/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 2103. Rings and Rods Used a 2D boolean array to track presence of colors (R, G, B) on each rod and counted rods containing all three. ⏱️ Time Complexity: O(n) 📦 Space Complexity: O(1) Strengthening understanding of mapping, indexing, and state tracking techniques. 💪 Consistency continues 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency

🔥 Day 58/100 Today’s problem: Reverse Integer (LeetCode) 💡 What I learned: - How to reverse digits using modulo (%) and division (/) - Handling negative numbers automatically - Most important: dealing with 32-bit integer overflow without using long - Learned to check overflow before updating the result ⚡ Key Concept: Before doing "rev = rev * 10 + digit", always check: 👉 If value exceeds "Integer.MAX_VALUE" or "Integer.MIN_VALUE", return 0 🧠 Takeaway: Small problems can hide tricky edge cases. Overflow handling is the real challenge here! 💻 Language used: Java #Day58 #100DaysOfCode #Java #DSA #CodingJourney #LeetCode

🚀 Day 27/100 Days of Code Challenge Today’s problem: Find Peak Element (Leetcode 162) 🔍 What I learned: How to find a peak element efficiently without scanning the entire array Using Binary Search to reduce time complexity from O(n) to O(log n) Understanding how the “slope” of elements helps decide the search direction 🧠 Key Idea: Instead of checking every element, compare the middle element with its neighbor: If nums[mid] < nums[mid + 1] → move right Else → move left ✅ Example: Input: [1, 2, 3, 1] Output: 2 (index of peak element 3) Consistency is key 🔑 — improving problem-solving skills one day at a time! 💪 #Day27 #100DaysOfCode #LeetCode #BinarySearch #DSA #Java #CodingJourney

Day 96 - LeetCode Journey Solved LeetCode 901: Online Stock Span in Java ✅ This problem is all about recognizing the pattern and using the right data structure. Instead of checking previous prices one by one, I used a Monotonic Stack to efficiently calculate spans. Every element is pushed and popped at most once → super optimized 🔥 Key idea: Keep removing smaller or equal previous prices and accumulate their spans. Key takeaways: • Monotonic Stack concept (very important) • Avoiding nested loops using stack optimization • Efficient span calculation • Thinking in patterns, not brute force ✅ All test cases passed ⚡ O(n) time and O(n) space This is one of those problems that truly levels up your stack game 💯 #LeetCode #DSA #Java #Stack #MonotonicStack #ProblemSolving #CodingJourney #InterviewPrep #Consistency #100DaysOfCode

🚀 Day 48 of My #LeetCode Journey Today’s problem: 2615. Sum of Distances 💡 Key Idea: Instead of calculating distances between equal elements using brute force (O(n²)), I used: HashMap to group indices of same values Prefix Sum to efficiently compute distances This reduced the complexity to O(n) 🔥 🧠 What I Learned: How prefix sums can optimize distance calculations Efficient handling of repeated elements Writing clean and optimized code using Java ⚡ Approach: Store indices of each number Use prefix sums to calculate left & right distances Combine both to get final answer 📈 Time Complexity: O(n) 📦 Space Complexity: O(n) Consistency is key. Small progress every day leads to big results 💪 #Day48 #Java #FullStackDeveloper #CodingJourney #100DaysOfCode #DSA #LeetCode

Day 91 - LeetCode Journey Solved LeetCode 61: Rotate List in Java ✅ This one is a classic linked list problem where the trick is to avoid brute force rotations. Instead of rotating step by step, I converted the list into a circular linked list, calculated the effective rotations using k % length, and then broke the list at the right position. Simple idea, but powerful optimization. Key takeaways: • Converting list into circular form for easy rotation • Using modulo to reduce unnecessary operations • Finding new tail and head efficiently • Clean pointer manipulation ✅ All test cases passed ⚡ O(n) time and O(1) space Problems like this teach how to think smarter, not harder 💡 #LeetCode #DSA #Java #LinkedList #CodingJourney #ProblemSolving #InterviewPrep #Consistency #100DaysOfCode