Implementing Majority Element with Boyer-Moore Voting Algorithm in Python

Day 48 of my #100DaysOfCode challenge 🚀 Today I implemented the Majority Element problem using the Boyer-Moore Voting Algorithm in Python. A majority element is the element that appears more than n/2 times in an array. What the program does: • Takes an array as input • Finds a potential majority candidate • Verifies if it actually appears more than n/2 times • Returns the majority element or None How the logic works: • Initialize count = 0 and candidate = None • Traverse the array: – If count == 0, set current number as candidate – If number equals candidate → increment count – Else → decrement count • This step finds a potential majority candidate • Traverse again to count its actual occurrences • If it appears more than n // 2 → return candidate • Otherwise return None Example: Input: [3, 2, 3] Output: 3 Another example: Input: [2, 2, 1, 1, 1, 2, 2] Output: 2 Another example: Input: [1, 2, 3, 4, 5] Output: None (No majority element) Why this algorithm is powerful: – Time Complexity: O(n) – Space Complexity: O(1) – Very efficient compared to brute force Key learnings from Day 48: – Understanding Boyer-Moore Voting Algorithm – Optimizing space complexity – Working with candidate selection logic – Solving real interview-level problems #100DaysOfCode #Day48 #Python #PythonProgramming #BoyerMoore #Algorithms #DataStructures #Arrays #ProblemSolving #CodingPractice #InterviewPrep #LearnByDoing #ProgrammingJourney #DeveloperGrowth #BTech #CSE #AIandML #VITBhopal #TechJourney

  • text

To view or add a comment, sign in

Explore content categories