Python Duplicate Element Finder with Set Operations

Day 24 of my #100DaysOfCode challenge 🚀 Today I worked on a Python program to find duplicate elements in a list. The goal was to detect repeated values efficiently without using nested loops. What the program does: • Takes a list of numbers • Uses a set to track seen elements • Identifies elements that appear more than once • Stores duplicate values in a separate list • Prints the duplicate elements How the logic works: 1)An empty list duplicates is created to store repeated elements 2)A set seen is initialized to track elements already encountered 3)The program iterates through each element in the list 4)If the element is already in seen, it is added to duplicates 5)Otherwise, it is added to the seen set 6)Finally, duplicates are printed (converted to set to avoid repetition in output) Example: Input: Input list: [1, 2, 2, 3, 4, 4, 5, 6, 6, 7] Output: Duplicate elements: [2, 4, 6] Why this approach is efficient: – Uses a set for O(1) average lookup time – Avoids nested loops – Time Complexity: O(n) Key learnings from Day 24: – Using sets for fast membership checking – Detecting duplicates efficiently – Writing optimized list-processing logic – Strengthening data structure fundamentals #100DaysOfCode #Day24 #Python #PythonProgramming #DataStructures #SetOperations #Algorithms #ProblemSolving #CodingPractice #LearnByDoing #ComputerScience #InterviewPrep #BTech #CSE #AIandML #VITBhopal #TechJourney

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