Counting Vowels in Java Using Streams

Java Puzzle for Today What will be the output of this program? String a = "Java"; String b = "Java"; String c = new String("Java"); System.out.println(a == b); System.out.println(a == c); System.out.println(a.equals(c)); Take a moment and guess before scrolling. Most beginners think the output will be: true true true But the actual output is: true false true Why does this happen? Because Java stores string literals in a special memory area called the String Pool. So when we write: String a = "Java"; String b = "Java"; Both variables point to the same object in the String Pool. But when we write: String c = new String("Java"); Java creates a new object in heap memory, even if the value is the same. That’s why: - "a == b" → true (same object) - "a == c" → false (different objects) - "a.equals(c)" → true (same value) Lesson: Use "equals()" to compare values, not "==". Small Java details like this can save you from real bugs in production. #Java #Programming #JavaPuzzle #Coding #SoftwareDevelopment

🚀 Day 5 of Java 8 Series 👉 Question: Find the frequency of each word in a given sentence using Java 8 Streams. import java.util.*; import java.util.function.Function; import java.util.stream.Collectors; public class WordFrequency {   public static void main(String[] args) {     String sentence = "java is great and java is powerful";     Map<String, Long> frequencyMap = Arrays.stream(sentence.split("\\s+"))         .collect(Collectors.groupingBy(             Function.identity(),             Collectors.counting()         ));     System.out.println(frequencyMap);   } } Output: {java=2, powerful=1, and=1, is=2, great=1} 🧠 Key Concepts Explained 👉 1. Arrays.stream() Converts an array into a Stream, which allows us to perform functional operations like filtering, grouping, and counting. In this example, after splitting the sentence into words, we use it to start the stream pipeline. 👉 2. split("\\s+") (Regex) \\s → matches any whitespace (space, tab, newline) + → matches one or more occurrences 💡 This ensures that even if there are multiple spaces between words, the sentence is split correctly into individual words. 👉 3. Collectors.groupingBy() This is used to group elements based on a key. Here, we group words by their value (Function.identity()) So all same words come under one group Example: java → [java, java] 👉 4. Collectors.counting() Used along with groupingBy() to count the number of elements in each group. Instead of storing a list of words, it directly gives the frequency #Java #Java8 #Streams #Coding #Developers #Learning

Same result. Half the code. Most Java developers don’t use this 😱 Java Fundamentals Series | Part 21 Can you spot the improvement? 👇 List<String> names = Arrays.asList( "Alice", "Bob", "Charlie" ); // ❌ Verbose Lambda names.forEach(name -> System.out.println(name)); // ✅ Method Reference names.forEach(System.out::println); Cleaner. More readable. More professional. 💪 4 Types of Method References 👇 // 1. Static method Function<Integer, Integer> abs = Math::abs; // 2. Instance method of object Function<String, String> upper = String::toUpperCase; // 3. Instance method of instance String prefix = "DBS: "; Function<String, String> addPrefix = prefix::concat; // 4. Constructor reference Function<String, StringBuilder> builder = StringBuilder::new; Real-world example 👇 // ❌ Lambda transactions.stream() .map(t -> t.getAmount()) .forEach(a -> System.out.println(a)); // ✅ Method Reference transactions.stream() .map(Transaction::getAmount) .forEach(System.out::println); Summary: 🔴 Writing lambdas everywhere 🟢 Use method references when method already exists 🤯 Cleaner code = fewer lines + better readability ⸻ 👉 Posting more real-world fixes like this. Have you used method references? Drop a :: below 👇 #Java #JavaFundamentals #BackendDevelopment #LearningInPublic #SDE2

Day 9 Java Practice: Find the First Non-Repeated Character in a String While practicing Java, I worked on a classic string problem: 👉 Find the first non-repeated character in a given string. For example, in the string "swiss", the first character that does not repeat is 'w'. To solve this, I used a LinkedHashMap to store character counts while preserving insertion order. Then I iterated through the map to find the first character with count = 1. ================================================== // Online Java Compiler // Use this editor to write, compile and run your Java code online import java.util.*; class Main {   public static void main(String[] args) {           String s="swiss";           char[] words=s.toCharArray();           Map<Character,Integer>map=new LinkedHashMap<Character,Integer>();           for(char word:words)     {      map.put(word,map.getOrDefault(word,0)+1);     }           for(Map.Entry<Character,Integer>entry:map.entrySet())     {       if(entry.getValue()==1)       {         System.out.println("First non-repeated character in the string is:"+entry.getKey());         break;       }     }               } } Output:First non-repeated character in the string is:w This was a good exercise to understand: Character frequency counting Importance of insertion order using LinkedHashMap String traversal logic #AutomationTestEngineer #Selenium #Java #CodingPractice #ProblemSolving

Hello Connections, Post 17 — Java Fundamentals A-Z This one confuses every Java developer at least once. 😱 Can you spot the bug? 👇 public static void addTen(int number) { number = number + 10; } public static void main(String[] args) { int x = 5; addTen(x); System.out.println(x); // 💀 5 or 15? } Most developers say 15. The answer is 5. 😱 Java ALWAYS passes by value — never by reference! Here’s what actually happens 👇 // ✅ Understanding the fix public static int addTen(int number) { number = number + 10; return number; // ✅ Return the new value! } public static void main(String[] args) { int x = 5; x = addTen(x); // ✅ Reassign the result! System.out.println(x); // ✅ 15! } But wait — what about objects? public static void addName(List<String> names) { names.add("Mubasheer"); // ✅ This WORKS! } public static void main(String[] args) { List<String> list = new ArrayList<>(); addName(list); System.out.println(list); // [Mubasheer] ✅ } 🤯 Java passes the REFERENCE by value! You can modify the object — but not reassign it! Post 17 Summary: 🔴 Unlearned → Java passes objects by reference 🟢 Relearned → Java ALWAYS passes by value — even for objects! 🤯 Biggest surprise → This exact confusion caused a method to silently lose transaction data! Have you ever been caught by this? Drop a 📨 below! #Java #JavaFundamentals #BackendDevelopment #LearningInPublic #SDE2 Follow along for more! 👇

Day14 Java Practice: Maximum Product of Three Elements in an Array While practicing Java, I solved an interesting array problem: 👉 Find the maximum product that can be formed using any three elements from the array. Example: Input: {10, 3, 5, 6, -20} At first, it looks like we just need the three largest numbers. But the twist is: negative numbers can change the result! 🧠 Key Idea: The product of two negative numbers becomes positive So we must compare: Product of the three largest numbers Product of two smallest (most negative) numbers and the largest number ================================================= // Online Java Compiler // Use this editor to write, compile and run your Java code online import java.util.*; class Main {   public static void main(String[] args) {     int a [] ={10,3,5,6,-20};     Arrays.sort(a);     int n=a.length;     System.out.println(Arrays.toString(a));     int result1=a[n-1]*a[n-2]*a[n-3];          int result2=a[0]*a[1]*a[n-1];          int result =Math.max(result1,result2);     System.out.println(result);        } } Output:[-20, 3, 5, 6, 10] 300 #JavaDeveloper #Arrays #CodingPractice #QualityEngineering #TechLearning

Hello Connections, Post 20— Java Fundamentals A-Z This one compiles perfectly. But breaks everything at runtime. 😱 Can you spot the bug? 👇 @FunctionalInterface interface Calculator { int calculate(int a, int b); int multiply(int a, int b); // 💀 Won't compile! } The bug? A Functional Interface can have only ONE abstract method! Two abstract methods = not functional! 💀 Here’s the fix 👇 // ✅ One abstract method only! @FunctionalInterface interface Calculator { int calculate(int a, int b); // ✅ Only one! } // ✅ Use it with Lambda! Calculator add = (a, b) -> a + b; Calculator multiply = (a, b) -> a * b; Calculator subtract = (a, b) -> a - b; System.out.println(add.calculate(5, 3)); // 8 ✅ System.out.println(multiply.calculate(5, 3)); // 15 ✅ System.out.println(subtract.calculate(5, 3)); // 2 ✅ Java’s Built-in Functional Interfaces // Predicate — returns boolean Predicate<String> isEmpty = s -> s.isEmpty(); // Function — transforms input to output Function<String, Integer> length = s -> s.length(); // Consumer — takes input, returns nothing Consumer<String> print = s -> System.out.println(s); // Supplier — no input, returns value Supplier<String> greeting = () -> "Hello DBS!"; Post 20 Summary: 🔴 Unlearned → Functional Interface can have multiple methods 🟢 Relearned → Exactly ONE abstract method — that’s what makes it functional! 🤯 Biggest surprise → Built-in functional interfaces replaced 20+ custom interfaces in codebase! Which built-in functional interface do you use most? Drop below! 👇 #Java #JavaFundamentals #BackendDevelopment #LearningInPublic #SDE2 Follow along for more! 👇

🚀 CyclicBarrier in Java — Small Concept, Powerful Synchronization In multithreading, coordination between threads is critical ⚡ 👉 CyclicBarrier allows multiple threads to wait for each other at a common point before continuing — ensuring everything stays in sync 🔥 💡 Think of it like a checkpoint 🏁 No thread moves forward until all have arrived! 🌍 Real-Time Example Imagine a report generation system 📊 Multiple threads fetch data from different APIs 📡 Each processes its own data ⚙️ Final report should generate only when all threads finish 👉 With CyclicBarrier, you ensure: ✅ All threads complete before aggregation ✅ No partial or inconsistent data ✅ Smooth parallel execution 💻 Quick Code Example import java.util.concurrent.CyclicBarrier; public class Demo { public static void main(String[] args) { CyclicBarrier barrier = new CyclicBarrier(3, () -> System.out.println("All threads reached. Generating final report...")); Runnable task = () -> { try { System.out.println(Thread.currentThread().getName() + " fetching data..."); Thread.sleep(1000); barrier.await(); System.out.println(Thread.currentThread().getName() + " done!"); } catch (Exception e) { e.printStackTrace(); } }; for (int i = 0; i < 3; i++) new Thread(task).start(); } } 💪 Why it’s powerful ✔️ Keeps threads perfectly synchronized ✔️ Prevents incomplete execution ❌ ✔️ Reusable for multiple phases ♻️ 🔥 Final Thought 👉 It’s a small but powerful feature — use it wisely based on your project needs to ensure the right level of synchronization without overcomplicating your design. #Java #Multithreading #Concurrency #BackendDevelopment #SoftwareEngineering

🚀 Java Trap: Why "finally" Doesn’t Change the Returned Value 👇 👉 Primitive vs Object Behavior in "finally" 🤔 Looks tricky… but very important to understand. --- 👉 Example 1 (Primitive): public static int test() { int x = 10; try { return x; } finally { x = 20; } } 👉 Output: 10 😲 Why not 20? 💡 Java stores return value before executing "finally" - "x = 10" stored - "finally" runs → changes "x" to 20 - But already stored value (10) is returned --- 👉 Example 2 (Object): public static StringBuilder test() { StringBuilder sb = new StringBuilder("Hello"); try { return sb; } finally { sb.append(" World"); } } 👉 Output: Hello World 😲 Why changed here? 💡 Object reference is returned - Same object is modified in "finally" - So changes are visible --- 🔥 Rule to remember: - Primitive → value copied → no change - Object → reference returned → changes visible --- 💭 Subtle concept… very common interview question. #Java #Programming #Coding #Developers #JavaTips #InterviewPrep 🚀

🚀 Java Puzzle: Why this prints "100" even after using "final"? 🤯 Looks like a bug… but it’s actually Java behavior 👇 👉 Example: final int[] arr = {1, 2, 3}; arr[0] = 100; System.out.println(arr[0]); // 100 😮 👉 Wait… "final" but still changing? 🤔 💡 Reality of "final": - "final" → reference cannot change - NOT → object data cannot change 👉 So: - ❌ "arr = new int[]{4,5,6}" → not allowed - ✅ "arr[0] = 100" → allowed --- 🔥 Now the REAL twist 😳 final StringBuilder sb = new StringBuilder("Java"); sb.append(" Developer"); System.out.println(sb); // Java Developer 😮 👉 Again changing despite "final" 🔥 Golden Rule: 👉 "final" means: - You cannot point to a new object - But you CAN modify the existing object 💡 Common misconception: 👉 Many think "final = constant" (NOT always true) 💬 Did you also think "final" makes everything immutable? #Java #JavaDeveloper #Programming #Coding #100DaysOfCode #TechTips #JavaTips #InterviewPrep #Developers #SoftwareEngineering