How to Count Operations to Zero with LeetCode Challenge

🚀 LeetCode Daily Challenge – Count Operations to Obtain Zero (#2169) 🧩 Problem Statement Given two integers num1 and num2, perform operations until either of them becomes 0. In one operation, if num1 >= num2, replace num1 = num1 - num2, else num2 = num2 - num1. Return the total number of operations performed. 💡 Approach : Instead of performing subtraction repeatedly (which is inefficient), we can directly calculate how many times one number can be subtracted from the other using integer division (/) and modulo (%). This idea is similar to the Euclidean Algorithm used to find the GCD of two numbers. Steps: While both num1 and num2 are not zero: Add num1 / num2 to the count (this represents how many subtractions happen at once). Update num1 = num1 % num2. Swap num1 and num2 to continue. Return the total count. ⏱️ Time Complexity: O(log(min(num1, num2))) — Each iteration reduces one of the numbers significantly (like in GCD). 💾 Space Complexity: O(1) — Constant extra space used. #LeetCode #Coding #DSA #Learning #ProblemSolving #Consistency

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