Maximizing House Robber Profit with Dynamic Programming

✅ Day 25 of 100 Days LeetCode Challenge Problem: 🔹 #198 – House Robber 🔗 https://lnkd.in/gNEG2NE4 Learning Journey: 🔹 Today’s problem focused on maximizing the amount of money that can be robbed without alerting the police by robbing adjacent houses. 🔹 I solved it using Dynamic Programming by keeping track of two states: robbing the current house or skipping it. 🔹 At each step, the decision is based on the maximum profit from previous houses. 🔹 This approach avoids recursion and efficiently computes the result in a single pass. Concepts Used: 🔹 Dynamic Programming 🔹 State Transition 🔹 Iterative Optimization 🔹 Space Optimization Key Insight: 🔹 Problems involving optimal choices often reduce to tracking previous states. 🔹 Using only two variables is sufficient to represent the entire DP state. 🔹 This results in an efficient solution with linear time and constant space complexity. #LeetCode #DataStructures #Algorithms #CodingInterview #SoftwareEngineering #SoftwareDeveloper #ProblemSolving #Programming #ComputerScience #TechCareers #100DaysOfCode #DailyCoding #Consistency #LearningInPublic #Python #BackendDevelopment #InterviewPreparation #TechCommunity

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Note: I accidentally uploaded the Day 24 (Climbing Stairs) image. The content is for Day 25 – House Robber. Apologies for the mix-up.

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