🚀 Java Trap: Why remove() in List can remove the WRONG element? 🤔 Looks simple… but can silently break your logic. Java List<Integer> list = new ArrayList<>(); list.add(10); list.add(20); list.add(30); list.remove(1); System.out.println(list); 👉 Output: [10, 30] Wait… we wanted to remove value 1, right? ❌ But Java removed index 1, not value 1. The reason is simple but tricky: remove(int index) // removes by index remove(Object o) // removes by value When you write list.remove(1), Java calls remove(int index). So how do you remove by value? list.remove(Integer.valueOf(20)); // ✅ correct or list.remove((Integer) 20); // ✅ ⚠️ Dangerous case: list.remove(10); This will throw IndexOutOfBoundsException because Java tries to remove index 10. 💡 Real takeaway: Method overloading + autoboxing can create subtle bugs. Always be clear whether you're removing by index or by value. 💬 Small mistake… big production issue. #Java #Programming #Coding #JavaTips #Developers
Method overloading the main purpose to achieve same work in different way like unlock our phone using fingerprint, pattern, password, pin
Prashant Panwar, >>> Why remove() in List can remove the WRONG element? Not WRONG element; the RIGHT element if You know how it works.Good post for beginners. System.out.println(list.remove(1)); // 20 System.out.println(list.remove((Integer)10)); // true System.out.println(list); // [30]