Java Set Removes Duplicates

🚀 Code 3 – #50LeetCodeChallenge Problem: 4Sum Given an array of integers and a target value, find all unique quadruplets that sum up to the target. Each element must be used only once, and the solution set should not contain duplicate combinations. 💡 Approach: Sort the array and use nested loops along with a two-pointer technique to find combinations efficiently. Skip duplicate elements to ensure only unique quadruplets are included. 📚 Key Takeaway: Combining sorting with the two-pointer approach helps reduce complexity and is highly effective for solving multi-sum problems like 4Sum. #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming

🚀 Code 5– #50LeetCodeChallenge 🧩 Problem: Remove Element Given an array and a value val, remove all occurrences of val in-place and return the count of remaining elements. The order of elements can be changed. 💡 Approach: Use a two-pointer technique—one pointer iterates through the array, while the other keeps track of the position to place elements that are not equal to val. 📚 Key Takeaway: In-place modification with two pointers helps achieve O(n) time complexity and O(1) space, making it efficient for array filtering problems. #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming

The Hidden Performance Killer: N+1 Query Problem The N+1 problem isn’t just a "junior mistake." I’ve seen it hidden in production systems at scale because it’s so easy to miss when you’re focused on making features work. #API #PerformanceOptimization #SoftwareEngineering, #SoftwareDevelopment, #Coding, #Programming, #BackendEngineering #Java #DatabaseOptimization #SpringBoot #CleanCode #WebDev #TechLearnings

🚀 Code 4 – #50LeetCodeChallenge 🧩 Problem: Remove Duplicates from Sorted Array Given a sorted array, remove duplicates in-place so that each unique element appears only once. Return the count of unique elements while maintaining the original order. 💡 Approach: Use the two-pointer technique—one pointer tracks the position of unique elements, while the other scans through the array. When a new unique element is found, place it at the correct position. 📚 Key Takeaway: Two-pointer approach is highly efficient for in-place array modifications, reducing space complexity to O(1) and time complexity to O(n). #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming

💡#LeetCode Daily Challenge – Smart Optimization! Today I worked on a problem where we need to find the minimum distance between three equal elements in an array. At first, it looks like a brute-force problem, but the real trick is simplifying the formula.After observing carefully, the distance formula actually reduces to just twice the difference between the first and last indices. So the middle element doesn’t even matter! That insight helped me avoid unnecessary computations.I grouped indices of each number and checked only consecutive triples to get the minimum distance efficiently. This problem reminded me how powerful pattern recognition can be in coding. #LeetCode #ProblemSolving #DataStructures #Algorithms #CodingInterview #Java #Programming #CodingJourney #TechLearning #Developers #SoftwareEngineering

🚀 Code 2 – #50LeetCodeChallenge Problem: "Longest Common Prefix" Given an array of strings, find the longest common prefix shared among all strings. If no common prefix exists, return an empty string "". 💡 Approach: Start with the first string as the prefix and compare it with the remaining strings. Gradually reduce the prefix until it matches the beginning of each string. 📚 Key Takeaway: String comparison and iterative reduction help efficiently solve prefix-based problems with optimal performance. #LeetCode #Java #Coding #ProblemSolving #Strings #Programming

🚀 Day 568 of #750DaysOfCode 🚀 🔍 Problem Solved: Two Furthest Houses With Different Colors Today’s problem looked simple at first, but it had a nice twist that tested observation skills more than brute force thinking. 💡 Key Insight: To maximize the distance between two houses with different colors, we don’t need to check all pairs. The answer will always involve either: the first house, or the last house Why? Because the maximum distance comes from the edges of the array. ⚡ Approach: Compare every house with the first and last house If colors are different → calculate distance Keep track of the maximum distance 🧠 Optimization: Instead of an O(n²) brute-force approach, we can solve this in O(n) time with constant space. 📈 Complexity: Time: O(n) Space: O(1) ✨ Takeaway: Sometimes the best solution isn’t about trying everything — it’s about spotting the right pattern. #LeetCode #Java #DSA #CodingJourney #ProblemSolving #100DaysOfCode #Programming #Tech #LearningEveryday

Check out this comprehensive breakdown of the new features in Java 26, including detailed examples for each JEP. Read the full guide here: https://lnkd.in/gs3Mz9Sa What features are you most excited about? Let's discuss in the comments! 👇 #Java #Java26 #SoftwareDevelopment #Programming #Coding #JavaTechOnline #BackendDevelopment #JDK26 #SoftwareArchitecture #TechnologyTrends

🚀 Day 561 of #750DaysOfCode 🚀 📌 Problem: Minimum Distance to the Target Element Today’s problem was simple yet a great reminder of how powerful basic iteration can be when applied correctly. 🔍 The task was to find the minimum distance between a given start index and any index i such that nums[i] == target. 💡 Key Insight: Instead of overthinking, just iterate through the array and track the minimum value of |i - start| whenever the target is found. Clean, efficient, and effective. 🧠 What I Learned: Sometimes brute force with clarity is the best solution Always look for opportunities to minimize operations with simple logic Writing clean and readable code matters as much as solving the problem ⚡ Approach: Traverse the array Check for target Update minimum distance ⏱️ Complexity: Time: O(n) Space: O(1) 💻 Consistency is key. Small steps every day build strong problem-solving skills over time. #leetcode #dsa #programming #java #coding #developers #softwareengineering #100daysofcode #codingjourney #tech #learning #growth

How do you solve problems where you need to try every possible combination? This is where Backtracking comes in. In this short video, I explained: - What is backtracking - How it works (try → explore → undo) - Real-world examples like N-Queens and Sudoku - Importance of pruning Backtracking is a powerful approach for solving complex constraint-based problems. Explore structured DSA in Java roadmap + practice: www.quipoin.com #DSA #Java #Programming #Coding #SoftwareEngineering #Algorithms #InterviewPreparation