🚀 Solved: Array Subset Problem | DSA Practice Today I solved an interesting Array problem based on checking whether one array is a subset of another. 🔹 Problem Statement: Given two arrays a[] and b[], determine whether b[] is a subset of a[]. 🔹 Approach I Used: Used a Dictionary (HashMap) to store the frequency of elements in array a Iterated through array b Checked availability and frequency of each element Returned True only if all elements satisfy the subset condition 🔹 Concepts Practiced: ✔️ Hashing ✔️ Frequency counting ✔️ Time complexity optimization ✔️ Clean Python implementation 💡 This approach reduces the time complexity to O(n + m) instead of using nested loops. Consistency in solving basic problems builds a strong foundation for advanced DSA and coding interviews. On to the next problem 💪 #DSA #Python #ProblemSolving #CodingJourney #LearningInPublic #PlacementPreparation
Array Subset Problem Solution with Hashing
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20 students. One simple Python problem. Most got it wrong. Which code gives the same output for both a and b? Code 1: a = [1, 2, 3] b = a b.append(4) print(a) Code 2: a = [1, 2, 3] b = a.copy() b.append(4) print(a) Take a guess before you run it. In interviews, questions are rarely difficult. They are designed to check one thing: Do you really understand the basics? Most people rush to answer. Very few stop and think. What’s your answer? #Python #CodingInterview #DataAnalytics #LearnPython #CareerGrowth
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Day 6/100 – #100DaysOfCode 🚀 Solved LeetCode #35 – Search Insert Position (Python). Today I practiced Binary Search to efficiently find the index of a target element in a sorted array. If the target is not present, return the position where it should be inserted. Approach: 1) Initialize two pointers: start and end. 2) Calculate mid index using (start + end) // 2. 3) If nums[mid] equals target, return mid. 4) If target is greater, move start to mid + 1. 5) Otherwise, move end to mid - 1. 6) If not found, return start as the correct insert position. Time Complexity: O(log n) Space Complexity: O(1) Binary Search is a must-know technique for technical interviews 💪 #LeetCode #Python #DSA #BinarySearch #ProblemSolving #100DaysOfCode
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🚀 DSA Practice – Check if Array is Sorted Today I worked on a simple yet important problem: Checking whether an array is sorted. 📌 Problem Statement: Given an array, determine if it is sorted in non-decreasing order. 🧠 My Approach: Traverse the array from left to right Compare each element with the next one If any element is greater than the next, the array is not sorted Otherwise, it is sorted ✅ ⚙️ Key Insight: A single pass through the array is enough — no need for sorting or extra space! 📊 Complexity: Time Complexity: O(n) Space Complexity: O(1) 💻 Language Used: Python ✨ Why this matters? This is a foundational concept used in: Optimizing algorithms Validating inputs Building efficient solutions in real-world problems Small problems like this help build strong fundamentals for coding interviews 💪 #DSA #Python #CodingPractice #Arrays #ProblemSolving #PlacementPreparation
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🚀 Day-75 of #100DaysOfCode 📊 NumPy Practice – Reversing an Array Without Slicing Today I implemented logic to reverse an array without using slicing, focusing on element swapping. 🔹 Concepts Practiced ✔ Array indexing ✔ Swapping logic ✔ In-place operations 🔹 Key Learning Avoiding built-in shortcuts helps in understanding core logic and problem-solving skills, which is very important for interviews. Step by step improving my problem-solving ability 🚀 #Python #NumPy #ProblemSolving #CodingChallenge #100DaysOfCode #PythonProgramming
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post 6 : GenAI interview experience questions: 1. what are LLMs? 2. python coding question on three sum in list 3. what is pretaining and fine-tuning? 4. tell me the steps involved in pretaining life cycle? 5. what is instruction tuning? 6. what are PEFT techniques? 7. explain LoRA and QLoRA and 4bit representation? what are singed and unsigned ? 8. RAG pipeline, Multimodal RAG , multivector retriever explain each.. 9. What is padding? 10. Compare FastAPI vs Flask Some questions related to projects... #GenAIinterviewquestions #AgenticAI, #MLops #followformoresuchinterviewquestions
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Solved the Continuous Subarray Sum problem on LeetCode using an optimized prefix sum and hashing approach. The solution checks whether a continuous subarray of size ≥ 2 has a sum divisible by k. By tracking remainders of prefix sums in a dictionary, the algorithm efficiently detects valid subarrays in O(n) time complexity. ✅ 102 / 102 test cases passed ⚡ Runtime: 46 ms (Beats 96.15%) 💻 Language: Python This problem strengthened my understanding of prefix sums, modular arithmetic, and hash map optimization techniques commonly used in algorithmic problem solving and technical interviews. #LeetCode #Python #Algorithms #DataStructures #CodingInterview #ProblemSolving
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Array Concatenation: When Readability Beats Built-in Methods Python offers nums + nums or nums * 2 for array concatenation, but explicit nested loops reveal the underlying operation's structure more clearly. This approach makes the "repeat twice" intent obvious and generalizes trivially to n repetitions. While not the most Pythonic, it demonstrates understanding of the fundamental operation rather than relying on language-specific shortcuts. The Interview Signal: Writing this version shows algorithmic thinking over language feature knowledge. Follow up by mentioning nums * 2 exists but you chose the explicit approach to demonstrate the operation clearly. Time: O(n) | Space: O(n) for output #CodeClarity #ExplicitVsImplicit #InterviewStrategy #ArrayOperations #Python #AlgorithmDesign #SoftwareEngineering
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Python Clarity Series – Episode 18 Topic: sort() vs sorted() 📌 Sorting confusion: sort() vs sorted() Students think they behave the same. They don’t. Example: nums = [4, 2, 1, 3] nums.sort() print(nums) Output: [1, 2, 3, 4] 👉 sort() changes the original list Now: nums = [4, 2, 1, 3] new_list = sorted(nums) print(new_list) Output: [1, 2, 3, 4] 👉 sorted() creates a new list Original list remains unchanged. 💡 Clarity Rule: sort() → modifies original sorted() → returns new list This is a classic Python interview question too. #PythonTips #ProgrammingConcepts #DeveloperThinking
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Did you know why range() in Python returns a range object instead of a list? It’s all about efficiency and memory optimization. Instead of storing every number in memory, range() generates values on demand making it lightweight, faster, and perfect for handling large sequences without slowing your program down. • This is a classic interview question that tests both your technical knowledge and your ability to explain concepts clearly. • Understanding these design choices helps you write smarter, more scalable code. • Next time you’re asked, you’ll know the answer: Python prioritizes performance and memory management. Save this tip before your next interview round it might just give you the edge you need! Visit itlearning.ai for more tips, insights, and resources designed to help you succeed. #itlearningai #PythonTips #PythonProgramming #CodeSmarter #LearnPython #PythonInterview #CodingBestPractices #PythonForBeginners #PythonDevelopers #InterviewPreparation #TechInterviews #CareerGrowth #CodingInterviews #JobReadySkills #InterviewTips #CareerDevelopment #AceYourInterview
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