Exploring Contribution Logic in Sum of Subarray Minimums with Divide and Conquer

Day 41 :- Exploring Contribution Logic: Sum of Subarray Minimums ✅ Today’s DSA session focused on a unique "Divide and Conquer" approach to a classic monotonic stack problem. I tackled 907. Sum of Subarray Minimums by shifting the focus from individual subarrays to the contribution of each element to the final sum. The Technical Breakdown: Contribution Technique: Instead of generating every possible subarray, I calculated how many subarrays have a specific element arr[minIdx] as their minimum. This is determined by the formula (minIdx - left + 1) * (right - minIdx + 1). Recursive Partitioning: By finding the global minimum in the current range [left, right], I calculated its total contribution and then recursively split the array into two halves: those to the left of the minimum and those to the right. Handling Duplicates: I used a strict "less than" check (arr[i] < arr[minIdx]) to consistently pick the first occurrence of a duplicate. This prevents double-counting subarrays when identical values are present. The Complexity Trade-off: While this recursive approach is highly intuitive and uses the Divide and Conquer paradigm, it can reach O(n^2) in the worst case (like a sorted array). This serves as a perfect conceptual bridge before moving toward the O(n) Monotonic Stack optimization! It's a great exercise in changing your perspective from "finding all subarrays" to "calculating the impact of each element"! 🚀 A huge thanks to my mentor, Anchal Sharma and Ikshit .. for the incredible support and for helping me stay consistent on this journey. Having that accountability makes all the difference! #DSA #Java #100DaysOfCode #DivideAndConquer #Recursion #ProblemSolving #Mentorship #LeetCode #SoftwareEngineering

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