High Performance SQL Query on LeetCode Beats 80% of Submissions

🚀 High Performance SQL Query on LeetCode! Just solved “Customer Placing the Largest Number of Orders” and this one felt extra satisfying 😄 📊 Result: ✔️ Accepted ✅ (19/19 test cases passed) ✔️ Runtime: 427 ms ⚡ ✔️ Beats ~80% of submissions 🚀 💡 Problem Insight: The task was to find the customer who placed the maximum number of orders — a great use case of GROUP BY + aggregation + subquery. 🧠 My Approach: Counted orders per customer Compared it with the maximum order count using a subquery Returned the customer with the highest count SELECT customer_number FROM Orders GROUP BY customer_number HAVING COUNT(order_number) = ( SELECT MAX(order_count) FROM ( SELECT COUNT(order_number) AS order_count FROM Orders GROUP BY customer_number ) AS temp ); 🔥 Key Takeaway: Combining aggregation + nested queries helps solve ranking-type problems efficiently. Consistency is paying off — step by step improving both logic and performance 💪 #SQL #LeetCode #CodingJourney #Database #Learning #Tech #PlacementPreparation #Consistency

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