Day 53 of #100DaysOfCode: Making Array Sum Divisible by K

🚀 Day 53 of #100DaysOfCode — Making Array Sum Divisible by K Hey everyone! 👋 Today’s challenge focused on a smart math-based optimization problem where the goal was to make the sum of an array divisible by a given number k using the minimum number of operations. 👨💻 What I practiced today: ✅ Understanding modulo (%) operations deeply ✅ Translating a problem into a simple mathematical observation ✅ Optimizing brute-force thinking into an O(n) solution ✅ Writing clean and minimal Python code 📌 Today’s Task: ✔ Given an integer array nums and an integer k ✔ In one operation, decrement any element by 1 ✔ Find the minimum operations required so that sum(nums) is divisible by k 🧠 Key Insight: If the sum of the array is S, then the minimum number of operations required is simply: S % k Because each operation reduces the sum by 1. 💡 Example: Input: nums = [3, 9, 7], k = 5 Sum = 19 → 19 % 5 = 4 Output: 4 ✨ Key Takeaway: Sometimes the best solution isn’t complex logic or loops — it’s recognizing a simple mathematical pattern. Mastering such observations can drastically reduce code complexity and runtime. #100DaysOfCode #Day53 #Python #LeetCode #ProblemSolving #MathInProgramming #CodingJourney #DSA #CleanCode

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