🚀Day 71 of #100DaysOfCode Today's challenge was LeetCode Problem #3228 - Maximum Number of Operations to Move Ones to the End. This problem focused on binary string manipulation and calculating the maximum possible operations under specific conditions. It tested the ability to analyze how '1's can be shifted past '0's efficiently while maintaining optimal time complexity. Key Learnings: Applied an efficient linear approach to avoid unnecessary simulations. Learned to track and update the count of '1's dynamically during iteration. Strengthened problem-solving strategies for string-based algorithmic questions. Language Used: Python Runtime: 55 ms (Beats 74.85%) Memory: 18.12 MB (Beats 54.49%) Day 70 represents continuous progress in improving logical reasoning and coding efficiency. Each solved problem builds a stronger foundation for advanced algorithmic thinking and real-world software development. #LeetCode #Python #ProblemSolving #CodingChallenge #100DaysOfCode #Algorithm #DataStructures #Mythyly
Solved LeetCode Problem #3228 with Python, improving coding efficiency and problem-solving skills.
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💻 Day 59 of #100DaysOfCode Solved LeetCode Problem 1716: Calculate Money in Leetcode Bank (Easy) 🏦 This problem involves a weekly incremental saving pattern — each Monday starts with a higher base deposit, and daily savings increase sequentially throughout the week. 🔹 Concepts Applied: Arithmetic Progression (AP) Modular division for week/day tracking Mathematical optimization (O(1) solution) ✅ Runtime: 0 ms — Beats 100% ✅ Memory: 17.94 MB This problem highlights how mathematical patterns can simplify what initially seems iterative into an elegant constant-time formula. #LeetCode #CodingJourney #Python #ProblemSolving #100DaysOfCode #MathematicsInProgramming #CodeOptimization #LearningEveryday
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🚀 Day 4/100 — Cracked LeetCode 1611: Minimum One Bit Operations to Make Integers Zero 🔥 Today’s challenge was a deep dive into bit manipulation and recursion. LeetCode 1611 looked deceptively simple—but beneath the surface, it’s a clever twist on Gray code transformations. 🔍 Problem Summary Transform an integer n into 0 using two constrained bit-flipping operations. The trick? You can only flip the rightmost bit, or flip the i-th bit if the (i-1)th is 1 and all lower bits are 0. 🧠 Key Insight This problem maps beautifully to recursive Gray code logic. For any number n, we recursively reduce it by flipping the highest set bit and subtracting the operations needed for the remainder. 📈 What I Learned Bitwise recursion can be elegant and powerful. Understanding binary patterns unlocks optimization. Python’s bit_length() is a hidden gem for bit-level logic. 🔧 Next Steps I’ll be documenting more of these insights as part of my 100-day challenge. If you’re into algorithmic puzzles or want to collaborate on clean, modular solutions—let’s connect! #100DaysOfCode #LeetCode #Python #BitManipulation #GrayCode #CodingChallenge #TechJourney #ScarBuilds
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🧠 Day 38 / 100 – Recursion: Factorial of a Number (LeetCode-#509) Today’s challenge was all about recursion — one of the most elegant concepts in programming. I revisited the Factorial problem, which beautifully demonstrates how a big problem can be broken into smaller subproblems. The idea is simple: 👉 The factorial of n is n * factorial(n-1) until n becomes 1. But the real challenge lies in understanding the flow of recursive calls and how the call stack unwinds to give the final result. This problem reminded me that recursion isn’t just about repeating a function — it’s about trusting the process and thinking in terms of smaller steps to solve complex problems. 🔍 Key Learnings Every recursive function must have a base case to prevent infinite loops. The call stack stores each recursive call until it’s resolved. Recursion is a natural fit for problems that can be divided into smaller, similar subproblems. 💭 Thought of the Day Recursion teaches patience and structure. Sometimes, you need to trust that solving the smaller version of a problem will help you conquer the big one — both in code and in life 💫. 🔗 Reference Problem:https://lnkd.in/g3yNGDbJ #100DaysOfCode #Day38 #LeetCode #Python #Recursion #Factorial #ProblemSolving #CodingChallenge #Algorithms #ProgrammingMindset #DataStructures #CleanCode #LearnByDoing #TechGrowth #PythonProgramming
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Complex problems often have elegant solutions hidden behind intimidating jargon. ✨ Today, I'm sharing a breakdown of the Strategy Design Pattern. 🚀 It's a fundamental tool that empowers you to write cleaner, more flexible code by making algorithms interchangeable. I've put together a user-friendly document that explains the 'what' 🤔, 'how' 🛠️, and 'where' 🗺️ of this pattern, backed by a real-world Python example. 🐍 Whether you're a seasoned pro or just starting out, I believe understanding this pattern will be a significant asset in your development toolkit. 💼 Let's dive in and elevate our coding practices together! 💡 Feel free to share your thoughts and questions below. 👇 #DesignPatterns #PythonDevelopers #StrategyDesignPattern #ContinuousLearning #SoftwareCraftsmanship #LowLevelDesign #HighLevelDesign #LLD #HLD #SoftwareDevelopment #NotificationSystem #WeekendLearning #Sunday #Python #SystemDesign #GenAI #AgenticAI
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🚀 Day 54 of #100DaysOfCode Solved LeetCode Problem 2011. Final Value of Variable After Performing Operations ✅ This problem tests simple yet essential programming logic — understanding how pre/post increment and decrement operations affect variable states. Given a list of operations like ["--X", "X++", "++X"], the goal is to compute the final value of X after applying all updates sequentially. 💡 Key Insight: Each operation (++X, X++) increases the value by 1, while (--X, X--) decreases it by 1. The implementation can be efficiently handled in O(n) time by iterating through the operations once. ⚙️ Result: Runtime: 0 ms ⚡ Beats 100% of Python submissions Memory Usage: 17.76 MB (Beats 60.70%) Another step forward in improving my algorithmic problem-solving and code optimization skills 💪 #LeetCode #Python #100DaysOfCode #CodingJourney #ProblemSolving #DailyPractice #TechLearning #MythylyCodes
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⏳ Leetcode #1611: Minimum One Bit Operations to Make Integers Zero 🔍 Today I picked up a problem that looked chaotic at first: transforming any integer into zero using very restricted bit-flip rules. Every bit could only flip if the bits below it satisfied certain conditions, making the process feel unpredictable 🧩. But once I dug deeper, something interesting appeared. The pattern wasn’t random at all; it was secretly following Gray Code. That realization turned a confusing sequence of operations into a clean, structured transformation ✨. ✅ Key Insight: The number of operations directly aligns with converting a Gray-Code-like representation of n into its binary form. ✅ Time Complexity: O(log n) ✅ Space Complexity: O(1) These are the moments that make problem solving rewarding: when the “why is this so messy?” suddenly becomes “this is actually lowkey clean” 🧠💡. #DataStructures #LeetCode #CodingChallenge #ProblemSolving #Python #DSA #ComputerScience #learningEveyDay
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🚀 Day 69 of #100DaysOfCode Solved LeetCode Problem #3542: Minimum Operations to Convert All Elements to Zero (Medium) Concepts Used: Stack Data Structure Efficient traversal and state management Understanding subarray operations Approach Summary: Iterated through each element while maintaining a stack to track increasing sequences. Incremented operation count whenever a new minimum appeared. This approach ensures minimum operations to reduce all elements to zero efficiently. Result: Accepted (Beats 85.71% in Runtime & 90.06% in Memory) Each day, one problem closer to mastery! #Python #LeetCode #100DaysOfCode #ProblemSolving #DataStructures #Algorithms #CodingJourney #MCA
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🚀 LeetCode #1526: Minimum Number of Increments on Subarrays to Form a Target Array Today I tackled an interesting Greedy Algorithm problem that really tests your ability to spot patterns and simplify complex logic. 🧩 Problem Brief: We start with an array of zeros and can increment any subarray by 1 in one operation. The goal is to form the target array using the minimum number of operations. 💡 Key Insight: Instead of simulating every operation, focus on how much each element increases compared to the previous one; each increase represents new operations needed. ⚙️ Formula: operations = target[0] + Σ(max(0, target[i] - target[i-1])) 🧠 Complexity: Time: O(n) Space: O(1) 🎯 Takeaway: Hard problems often become simple once you recognize the pattern behind the process. #LeetCode #Python #DSA #Coding #ProblemSolving #GreedyAlgorithm #LearningEveryday
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✨ Leetcode #3370: Smallest Number With All Set Bits Today, I solved an interesting bit manipulation problem where the task was to find the smallest number greater than or equal to a given n, such that its binary representation contains only set bits (1s). 🔍 Concept Overview: - This problem beautifully highlights the power of bit manipulation and mathematical insight. - The key lies in observing the pattern of numbers that have all bits set, like 1, 3, 7, 15, 31, etc. - These numbers can be represented in a uniform mathematical form, which makes the solution both elegant and efficient. 💡 Key Learning: - Understanding how bit shifting and logarithmic operations can simplify problems involving binary representations. - Reinforcing the importance of pattern recognition in bit level problems. - Appreciating how a constant time solution can emerge from strong mathematical reasoning. 🧠 Complexity: O(1) A pure logic based solution; concise, optimal, and satisfying! #LeetCode #BitManipulation #Coding #ProblemSolving #Python #LearningEveryday #DataStructuresAndAlgorithms
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🚀#3217: Delete Nodes from Linked List present in an Array Recently, I explored an interesting problem involving the removal of specific nodes from a linked list based on a given list of values. 💡 Problem Overview: Given a linked list and a list of numbers nums, the task is to delete all nodes whose values are present in nums. 🔍 Approach Summary: 1️⃣ Convert nums into a set for constant time lookups. 2️⃣ Traverse the linked list using two pointers, curr (current node) and prev (previous node). 3️⃣ If the current node’s value is in the set: - If it’s the head, move the head forward. - Otherwise, link the previous node to the next node, effectively removing the current one. 4️⃣ Continue traversing until all matching nodes are removed. ✨ Key Learnings: - Utilizing a set improves efficiency for value lookups. - Careful handling of the head node prevents pointer issues. - Clean traversal logic leads to better readability and fewer edge case errors. #Python #DataStructures #LinkedList #Coding #ProblemSolving #LeetCode #DSA #LearningJourney
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