Java Dynamic Programming Solution for Coin Change II

Day 94/100 – #100DaysOfCode 🚀 | #Java #DynamicProgramming #UnboundedKnapsack ✅ Problem Solved: Coin Change II (LeetCode 518) 🧩 Problem Summary: Given an integer amount and an array of coin denominations, return the number of combinations that make up the amount. Each coin can be used unlimited times, and the order of coins does not matter. 💡 Approach Used: ✔ Used Dynamic Programming (1D DP) ✔ This is a classic Unbounded Knapsack problem Steps: Initialize dp[0] = 1 (one way to make amount 0) For each coin: Iterate from coin to amount Update dp[i] += dp[i - coin] This ensures combinations are counted, not permutations ⚙ Time Complexity: O(N × amount) 📦 Space Complexity: O(amount) (where N = number of coins) ✨ Takeaway: The order of loops in DP matters! Iterating coins first avoids counting duplicate permutations and keeps combinations unique. #Java #LeetCode #DynamicProgramming #UnboundedKnapsack #100DaysOfCode #CodingChallenge

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