Mitul Ranpariya’s Post

Most developers say HashMap operations are O(1). That’s not always true. And this misunderstanding shows up in interviews and real systems. Let’s break down what actually happens inside a HashMap: Internally, HashMap uses an array of buckets: Node<K, V>[] table (default size = 16) Each bucket stores a structure like: class Node<K, V> { int hash; K key; V value; Node<K, V> next; } When you insert a key-value pair: 1.Hash value is calculated from the key 2.Bucket index is found using: hash % capacity 3.Entry is placed in that bucket Now the critical part: What if multiple keys map to the same bucket? 👉 Collision happens Entries are stored as a LinkedList using the next pointer If collisions increase → performance degrades Worst case: 👉 All keys land in same bucket → O(n) To handle this, Java introduced optimizations: Load Factor = 0.75 → When no. Entries > capacity * 0.75 → rehashing happens → Capacity doubles → reduces collisions Treeify Threshold = 8 → If a bucket has more than 8 entries → LinkedList converts into Red-Black Tree Now complexity improves: 👉 From O(n) → O(log n) So the reality is: Best case → O(1) Worst case → O(n) Optimized worst case → O(log n) Challenge: So what is Internal structure of LinkedHashMap ? Let’s see how you think about internal design 👇 #Java #BackendDevelopment #SoftwareEngineering #SystemDesign #HashMap #JavaDeveloper

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