Mastering Java with LeetCode: Hashing and Data Structures

🚀 Mastering Java Through LeetCode Day 19 Today I solved an interesting problem that helped me strengthen my understanding of Hashing and Data Structures. 📌 LeetCode Q. 2215 – Find the Difference of Two Arrays 🔍 Problem Insight: Given two arrays, the task is to find: ✔️ Elements present in nums1 but NOT in nums2 ✔️ Elements present in nums2 but NOT in nums1 👉 And return only distinct values 💡 Approach I Used: Used HashMap to store unique elements Checked presence using containsKey() (O(1) lookup) Built two result lists efficiently Why this approach? Hashing reduces time complexity and avoids duplicate handling manually. Key Learning: Sometimes choosing the right data structure (HashMap/HashSet) makes the solution clean, fast, and interview-ready. Complexity: Time: O(n + m) Space: O(n + m) Pro Tip: Using HashSet can make the solution even more optimized and readable. Consistency is not about perfection, it's about showing up every day and improving 1% #DSA #Java #LeetCode #CodingJourney #100DaysOfCode #Programming #SoftwareEngineer #Coding #Developers #HashMap #Learning #Tech #PlacementPreparation #CDAC #OpenToWork

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