Designing a HashSet in C++ for #100DaysOfCode

📅 Day 33 of #100DaysOfCode Problem: Basic Calculator (LeetCode 224) Approach: 1️⃣ Parsed the string character by character, keeping track of current number, sign, and result. 2️⃣ When encountering '+' or '-', added the previous number to the result and reset the current number. 3️⃣ Used a stack to handle parentheses — pushed the current result and sign when '(' was found, then restored them after ')'. 4️⃣ Carefully computed the final result by adding the last pending number after traversal. #100DaysOfCode #LeetCode #DSA #ProblemSolving #Stack #Cplusplus #CodingChallenge #Algorithms #Math #CodeNewbie #Programming #SoftwareEngineering #CodingJourney #TechCommunity #DeveloperLife #KeepLearning #LearningInPublic #Motivation

📅 Day 51 of #100DaysOfCode Problem: Number of Substrings That Satisfy (LeetCode 3280) Approach: 1️⃣ Precomputed cumulative counts of 1s using a prefix sum array. 2️⃣ For each substring [i...j], calculated both the number of 0s and 1s. 3️⃣ Used a smart optimization: If (zero² > one), skip forward — those substrings can’t satisfy the condition. If (zero² == one) or (zero² < one), count and move ahead efficiently. 4️⃣ This drastically reduced redundant iterations compared to a naïve O(n³) brute force. #100DaysOfCode #LeetCode #DSA #ProblemSolving #Cplusplus #CodingChallenge #Algorithms #MathLogic #BinaryString #Programming #DeveloperLife #CodingJourney #CodeNewbie #DailyDSA #SoftwareEngineering #KeepLearning #GrowthMindset #Motivation #TechCommunity

📅 Day 35 of #100DaysOfCode Problem: Search in Rotated Sorted Array II (LeetCode 81) Approach: 1️⃣ First, handled duplicates by skipping consecutive equal elements from both ends to avoid confusion while finding the rotation point. 2️⃣ Used a modified binary search to find the pivot (the smallest element’s index) — this separates the rotated parts of the array. 3️⃣ Performed binary search on both halves — before and after the pivot — to check where the target lies. 4️⃣ Returned true if found in either part, else false. #100DaysOfCode #LeetCode #BinarySearch #RotatedArray #ProblemSolving #Algorithms #DSA #Cplusplus #CodingChallenge #Programming #DeveloperLife #CodeNewbie #DailyDSA #TechCommunity #KeepLearning #SoftwareEngineering #LearningInPublic #Motivation

💡 Day 84 of My LeetCode Journey – Problem 1614: Maximum Nesting Depth of Parentheses Today’s problem tested my understanding of stack concepts and string traversal — determining how deeply parentheses are nested in a given string. 🧠 Concept: The idea is simple yet elegant: Traverse the string character by character. Use a counter to track the number of open parentheses (. Update the maximum depth whenever the count increases. Decrease the counter when a closing parenthesis ) appears. Example: "(1+(2*3)+((8)/4))+1" → Maximum depth = 3 ✅ Key Takeaways: Strengthened understanding of parentheses matching and depth counting. Improved ability to simulate stack behavior without extra space. Reinforced skills in clean logic implementation and iteration control. Small yet powerful problems like this sharpen clarity, precision, and logical thinking 🧩 #LeetCode #ProblemSolving #100DaysOfCode #DSA #CodingChallenge #Programming #LogicBuilding #Cplusplus #DailyCoding #LearningEveryday

📅 Day 48 of #100DaysOfCode Problem: Search in Rotated Sorted Array II (LeetCode 81) Approach: 1️⃣ First, used a pivot function to find the smallest element’s index, skipping duplicate values on both sides. 2️⃣ Once the pivot was found, split the array into two sorted parts. 3️⃣ Applied normal binary search on both halves to find the target. 4️⃣ Combined both steps to handle rotations and duplicates efficiently. #100DaysOfCode #LeetCode #DSA #ProblemSolving #BinarySearch #Cplusplus #CodingChallenge #Algorithms #Programming #DeveloperLife #CodeNewbie #SoftwareEngineering #CodingJourney #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

📅 Day 28 of #100DaysOfCode 🚀 Problem: 49. Group Anagrams (LeetCode) Approach: -> For each string, sort its characters — the sorted version acts as a unique key for its anagram group. -> Store all words with the same sorted key inside a hash map (unordered_map<string, vector<string>>). -> After processing all words, collect all grouped values from the map into a result vector. ->This leverages hashing + sorting for efficient grouping — O(n * k log k) where k is average string length. #100DaysOfCode #LeetCode #DSA #ProblemSolving #Cplusplus #CodingChallenge #Algorithms #DataStructures #Hashing #StringManipulation #CodingCommunity #Programming #DeveloperLife #LearnToCode #TechCommunity #DailyDSA #CodeNewbie #SoftwareEngineering #CodingJourney #Consistency #KeepLearning #LearningInPublic #GrowthMindset #Motivation

📅 Day 42 of #100DaysOfCode Problem: Subsets (LeetCode 78) Approach: 1️⃣ Used backtracking to explore every possibility — either include the current element or skip it. 2️⃣ When the index reaches the end, added the current subset to the result. 3️⃣ Backtracked properly to remove elements before exploring the next choice. 4️⃣ This ensures every possible combination is covered without duplicates. #100DaysOfCode #LeetCode #Backtracking #Recursion #DSA #Cplusplus #ProblemSolving #CodingChallenge #Algorithms #Programming #DeveloperLife #CodeNewbie #DailyDSA #TechCommunity #KeepLearning #GrowthMindset #SoftwareEngineering #LearningInPublic #Motivation

📅 Day 41 of #100DaysOfCode Problem: Merge k Sorted Lists (LeetCode 23) This one was all about optimization and clean recursion. Instead of merging lists one by one, I used a divide and conquer approach merge them in pairs, just like merge sort. Approach: 1️⃣ If there’s only one list, return it - base case. 2️⃣ Split the range of lists into two halves using recursion. 3️⃣ Merge both halves using a helper function that merges two sorted lists. 4️⃣ Keep dividing until everything is combined into one sorted list. #100DaysOfCode #LeetCode #DSA #Cplusplus #ProblemSolving #DivideAndConquer #Recursion #CodingChallenge #Algorithms #Programming #CodeNewbie #DeveloperLife #LearningInPublic #KeepLearning #SoftwareEngineering #TechCommunity #DailyDSA #GrowthMindset #Motivation

📅 Day 31 of #100DaysOfCode Problem: Reverse Pairs (LeetCode 493) Approach: 1️⃣ Divide the array using merge sort to count pairs efficiently. 2️⃣ Count cross-pairs where nums[i] > 2 * nums[j] while merging. 3️⃣ Merge the halves back in sorted order to maintain correct comparisons. 4️⃣ Sum up counts from left, right, and cross halves for the final result. #100DaysOfCode #LeetCode #DSA #ProblemSolving #Cplusplus #CodingChallenge #Algorithms #Programming #DeveloperLife #CodeNewbie #DailyDSA #SoftwareEngineering #CodingJourney #LearningInPublic #TechCommunity #KeepLearning #DivideAndConquer #GrowthMindset #Motivation

📅 Day 47 of #100DaysOfCode Problem: Combination Sum II (LeetCode 40) Approach: 1️⃣ Sorted the array to handle duplicates easily. 2️⃣ Used recursion to explore each number — either include it or skip it. 3️⃣ Reduced the target as I added elements, and when the target hit 0, that path became a valid combination. 4️⃣ Skipped duplicates using a simple check: if (i > idx && candidates[i] == candidates[i-1]) continue. #100DaysOfCode #LeetCode #DSA #ProblemSolving #Backtracking #Recursion #Cplusplus #CodingChallenge #Algorithms #Programming #DeveloperLife #CodeNewbie #SoftwareEngineering #DailyDSA #CodingJourney #KeepLearning #TechCommunity #Motivation #GrowthMindset