How HashMap Works Internally in Java: A Simple Explanation

𝗛𝗼𝘄 𝗛𝗮𝘀𝗵𝗠𝗮𝗽 𝗪𝗼𝗿𝗸𝘀 𝗜𝗻𝘁𝗲𝗿𝗻𝗮𝗹𝗹𝘆 𝗶𝗻 𝗝𝗮𝘃𝗮? I recently watched a video from Concepts & Coding by Shrayansh Jain — he explained the internal working of HashMap in a very simple way. Here’s what I learned👇 🎥 Video link:https://lnkd.in/gmQ3qe8a 1️⃣ When we create a HashMap without a size, Java creates an internal array of 16 buckets by default. Each bucket is a place where data entries are stored. 2️⃣ When we call put(key, value) — Java first calculates the hash code of the key. Then it spreads the hash evenly using (hash >>> 16). After that, it finds the bucket index using (n - 1) & hash — this is faster than using %, because the array size is always a power of 2. Finally, the entry is stored as a Node (which keeps hash, key, value, and next). 3️⃣ If the same key is added again — Java checks hashCode() to find the right bucket. Then it uses equals() to check if the key already exists. If it matches, the value is updated. 4️⃣ If there’s a collision (different key but same bucket): The new entry is added to the linked list at that bucket. If the list size becomes 8 or more (and total size ≥ 64), it converts into a Red-Black Tree for faster lookups. 5️⃣ When the map fills up beyond 75% of its capacity (load factor = 0.75) — Java performs rehashing: doubles the array size and re-inserts all entries, because their new index changes. 6️⃣ Time complexity: Average → O(1) Worst case → O(log n) (if tree used) or O(n) (in linked list) 💡 HashMap looks simple, but it’s one of the most efficient and well-designed data structures in Java. #Java #HashMap #DataStructure #CollectionsFramework #BackendDevelopment #CodingConcepts #CleanCode #techieanky #javainterviewquestion #grow #linkedin

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