LeetCode #33: Rotated Sorted Array Search in Python

LeetCode #33 – Search in Rotated Sorted Array | Python Implementation I implemented a modified binary search to handle rotated sorted arrays. At each step, we determine which half of the array is properly sorted by comparing nums[l] with nums[mid]. Once the sorted half is identified, we check if the target falls within that range — if yes, we search that half; otherwise, we search the other half. This preserves the O(log n) complexity despite the rotation. This pattern is crucial in distributed systems for searching circularly-buffered logs, time-series databases with wraparound indices, and cache eviction policies with rotational priority queues. Key Takeaway: The critical insight is determining which side is sorted at each iteration using nums[l] <= nums[mid]. Once identified, standard binary search range logic applies. This demonstrates how binary search can be adapted to non-standard sorted structures while maintaining logarithmic complexity. Time: O(log n) | Space: O(1) #LeetCode #DataStructures #Python #BinarySearch #Arrays #CodingInterview #ProblemSolving #SoftwareEngineering

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