Optimize 3Sum from O(n³) to O(n²) with Sorting and Two Pointers

Reducing 3Sum from O(n³) to O(n²): The Power of Sorting + Two Pointers Most developers first approach 3Sum with nested loops, hitting O(n³) complexity. The breakthrough: sort the array first, then reduce it to n iterations of the Two Sum problem. For each element as the fixed anchor, use two pointers on the remaining sorted portion to find pairs that complete the triplet. Sorting unlocks directional movement (move left if sum too high, right if too low), collapsing a dimension of complexity. The Critical Detail: Duplicate handling isn't just about correctness — it's about recognizing that sorted order lets you skip duplicates in O(1) rather than using a HashSet for deduplication. The while nums[l] == nums[l-1] skip after finding a valid triplet prevents processing identical combinations. Time: O(n²) | Space: O(1) excluding output #AlgorithmOptimization #TwoPointers #Sorting #ComplexityReduction #Python #CodingInterview #SoftwareEngineering

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